The density of an object is the ratio of its mass over the volume. This translates to the amount of substance present in a certain space and can mathematically be expressed as,
density = mass / volume
In this item, we are given that the object of mass 1.41 kg is able to displace 0.314 L of liquid. The volume of water displaced is also the volume of the object. Hence,
density = 1.41 kg / 0.314 L = 4.49 kg/L
Then, we convert the calculated volume of g/mL.
density = (4.49 kg/L)(1 L / 1000 mL)(1000 g/1 kg)
<em> density = 4.49 g/mL</em>
y = y0 +v0*t +0.5at^2
where y0 = initial vertical position = 22m
y = final vertical position = 0m
v0 = initial vertical velocity = 0 m/s
a = acceleration = -9.8 m/s^2
t = time in seconds
0 = 22 +0*t + 0.5(-9.8)t^2
t^2 = 22/4.9 = 4.49 s^2
t = 2.12 s
So it traveled 35m in 2.12 s
the horizontal distance traveled is determined by:
x = x0 +v0*t +0.5at^2
but here a in the horizontal direction is 0 m/s^2
and v0 is in the velocity in the horizontal direction in this equation
35 m = 0 +v0*t
35 m = v0(2.12 s)
v0 = 16.5 m/s
So the ball was kicked 16.5 m/s in the horizontal direction
Answer:
Radius of aluminium sphere which has same mass as of sphere of iron with radius 14 m is 40.745 meters.
Explanation:
Let the radius of aluminium sphere be
From the relation between density, mass and volume we know that
Applying equation 'i' separately to iron and aluminium sphere we get
Equating the masses of iron and aluminium spheres we get
Answer:
4E
Explanation:
From the question given above, the following data were obtained:
Initial elongation (e₁) = 4 cm = 4/100 = 0.04 m
Initial energy (E₁) = E
Final elongation (e₂) = 0.04 + 0.04 = 0.08 m
Final energy (E₂) =?
The energy stored in a s spring is given by:
E = ½Ke²
Where
E => is the energy
K => is the spring constant
e => is the elongation
From:
E = ½Ke²
Energy is directly proportional to the elongation. Thus,
E₁/e₁² = E₂/e₂²
With the above formula, we can obtain the final energy as follow:
Initial elongation (e₁) = 0.04 m
Initial energy (E₁) = E
Final elongation (e₂) = 0.08 m
Final energy (E₂) =?
E₁/e₁² = E₂/e₂²
E / 0.04² = E₂ / 0.08²
E / 0.0016 = E₂ / 0.0064
Cross multiply
0.0016 × E₂ = 0.0064E
Divide both side by 0.0016
E₂ = 0.0064E / 0.0016
E₂ = 4E
Therefore, the final energy is 4 times the initial energy i.e 4E
Answer:
Elastic collision
Explanation:
The interaction of two particles is called collision. There are two types of collision i.e. elastic collision and inelastic collision.
Two bouncy balls colliding with each other is an example of elastic collision. In this type of collision the momentum and kinetic energy of the bodies remains constant i.e.
and
Where
m₁ and m₂ are masses of two balls A and B
u₁ and u₂ are initial velocities of ball A and B
v₁ and v₂ are final velocities of ball A and B