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3 years ago

PLEASE HURRY ITS FOR A QUIZ

Physics

2 answers:

swat323 years ago

4 0

The answer is C! I got it right!

nalin [4]3 years ago

3 0

The answer is C. at the Speed of light, 300,000,000 m/s

You need to know that there exists a large family of waves, each with a different wavelength range, called the electromagnetic spectrum (sometimes shortened to the e-m spectrum). These waves all travel at the speed of light (300,000,000 metres per second) in a Vacuum

Good Luck on your test btw

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An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro

Mashutka [201]

1) The distance travelled by the electron is $1\cdot 10^{17} m$

2) The time taken is $4.0\cdot 10^{10}s$

Explanation:

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

$u=5\cdot 10^6 m/s$ is the initial velocity

v = 0 is the final velocity (it comes to a stop)

$a=-1.25\cdot 10^{-4} m/s^2$ is the acceleration

Solving for s, we find the distance travelled:

$s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m$

The total time taken for the electron in its motion can also be found by using another suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

$u=5\cdot 10^6 m/s$

v = 0

$a=-1.25\cdot 10^{-4} m/s^2$

And solving for t, we find the time taken:

$t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s$

Learn more about accelerated motion:

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#LearnwithBrainly

7 0

3 years ago

a light wave is traveling straight up out of the ocean then moves out into the air how do you expect the movement of the light w

Mariulka [41]

If the light is traveling straight up, then it hits the interface (surface
or boundary) between water and air perpendicularly (90° to the surface).

This direction is the direction of the 'normal' to the surface. So the
angle of incidence is zero, and that means the angle of refraction is
also zero. The light just keeps going in the same direction when it
emerges into the air, and is not bent.

However, its speed increases in air, and that means its wavelength
also becomes longer than it was in the water.

6 0

4 years ago

How is weather and climate alike

Zarrin [17]

Both climate and weather measure conditions in the atmosphere.

6 0

3 years ago

The highest barrier that a projectile can clear is 19.7 m, when the projectile is launched at an angle of 15.0o above the horizo

svlad2 [7]

Answer:

76 m /s

Explanation:

maximum height, H = 19.7 m

Angle of projection, θ = 15 degree

Let u be the projectile launch speed

Use the formula of maximum height

$H = u^{2}Sin\theta ^{2}/2g$

$19.7 = u^{2}Sin^{2}15/19.6$

u = 75.9199 = 76 m /s

6 0

3 years ago

Which of the following best describes seamounts and islands of the deep ocean basins?

Rina8888 [55]

Answer: The correct option is (d)

lava flows built up from the ocean floor by multiple, summit and flank eruptions

Explanation:

Piles of baseltic lava flows built up from the ocean floor by multiple summit and flank eruptions describes seamounts and islands of the deep ocean basins.

4 0

4 years ago

*PLEASE HURRY ITS FOR A QUIZ*

PLEASE HURRY ITS FOR A QUIZ