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3 years ago

PLEASE HURRY ITS FOR A QUIZ

Physics

2 answers:

swat323 years ago

4 0

The answer is C! I got it right!

nalin [4]3 years ago

3 0

The answer is C. at the Speed of light, 300,000,000 m/s

You need to know that there exists a large family of waves, each with a different wavelength range, called the electromagnetic spectrum (sometimes shortened to the e-m spectrum). These waves all travel at the speed of light (300,000,000 metres per second) in a Vacuum

Good Luck on your test btw

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Driving on asphalt roads entails very little rolling resistance, so most of the energy of the engine goes to overcoming air resi

Bad White [126]

A) Agreed.
b) Value agreed but units should be W (watts). 

c) Here's one method... 

15 miles = 24140 m 

1 gallon of gasoline contains 1.4×10⁸ J. 

So moving a distance of 24140m requires gasoline containing 1.4×10⁸ J 

Therefore moving a distance of 1m requires gasoline containing 1.4×10⁸/24140 = 5800 J 

Overcoming rolling resitance for 1m requires (useful) work = force x distance = 1000x1 = 1000J 

So 5800J (in the gasoline) provides 1000J (overcoming rolling resistance) of useful work for each metre moved. 

Efficiency = useful work/total energy supplied 
= 1000/5800 
= 0.17 (=17%)

8 0

4 years ago

A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark

Digiron [165]

Answer:

16 cm

Explanation:

Given that,

The object begins from 0 and moves 3cm towards left side followed by 7 cm towards the right and then, 6 cm towards the left side.

Let the x-axis to be the +ve and on the right side and -ve on the left

Thus, displacement would be:

= 0 -3 + 7 -6

= -2 cm

This implies that the object displaces 2cm towards the left.

While the total distance covered by the object equal to,

= 0cm + 3cm + 7cm + 6cm

= 16 cm

Thus, 16 cm is the total distance.

3 0

3 years ago

Is motion on earth different from space

Rus_ich [418]

It's not that the laws of motion are any different on Earth than in space. But Earth's gravitational field has such an overwhelming force it masks their precise effects. And gravity is integral to all sorts of phenomena that we take for granted.

8 0

3 years ago

A relaxed spring of length 0. 13 m stands vertically on the floor; its stiffness is 1180 N/m. You release a block of mass 0. 5 k

Daniel [21]

The length of spring when the block comes momentarily to rest on the compressed spring will be 0.054 m.The length of the spring by the letter x.

<h3>What is the potential energy of the spring?</h3>

The energy is stored in the spring when it is stretched or compressed by some length. It is the product of mass, gravity and distance compressed or stretched. Mathrmatically it is given by;

PE=mgh

The given data in the problem is ;

m is the mass of the block is 0.5 kg height,

h is the height is released is 0.7 m

x initial length of the spring = 0.13 m.

K is the force constant of the spring = 1180 N/m.

By the law of conservation of energy,

The potential energy of the spring gets converted

$\rm mgh=\frac{1}{2}KL^2 \\\\ \rm L= \sqrt{\frac{2mgh}{K} } \\\\ \rm L= \sqrt{\frac{2\times 0.5\times9.81 \times 0.7}{1180} \\\\ \\\\$

$\rm L= 0.054m$

Hence the length of spring when the block comes momentarily to rest on the compressed spring will be 0.054 m

To learn more about the potential energy of the spring refer to the link;

brainly.com/question/2730954

4 0

2 years ago

a 3.18-kg rock is released from rest at a height of 26.6 m. ignore air resistance and determine (a) the kinetic energy at 26.6 m

antiseptic1488 [7]

Answer:

(a) 0 J

(b) 828.96 J

(c) 828.96 J

(d) 828.96 J

(e) 0 J

(f) 828.96 J

Explanation:

Given:

Mass of the rock is, $m=3.18\ kg$

Initial height of the rock is, $h_{i}=26.6\ m$

Final height of the rock is, $h_f=0\ m$

Initial velocity of the rock is, $v_i=0\ m/s(Rest)$

Acceleration due to gravity is, $g=9.8\ m/s^2$

(a)

Initial kinetic energy is given as:

$K_i=\frac{1}{2}mv_i^2$

Plug in the given values and solve for ' $K_i$ '. This gives,

$K_i=\frac{1}{2}\times 3.18\times 0^2=0$

Therefore, initial kinetic energy is 0 J.

(b)

Initial potential energy is given as:

$U_i=mgh_i\\U_i=3.18\times 9.8\times 26.6=828.96\ J$

Therefore, initial potential energy is 828.96 J.

(c)

Mechanical energy is equal to the sum of kinetic and potential energy. It is always a constant value. Therefore,

$ME=K_i+P_i\\ME=0+828.96=828.96\ J$

Therefore, mechanical energy at 26.6 m is 828.96 J.

(d)

Now, at the final height of 0 m, the decrease in potential energy will be equal to the increase in the kinetic energy. In other words, the potential energy at the start will be converted to kinetic energy at the bottom.

Therefore, kinetic energy at the 0 m is given as:

$K_f=U_i=828.96\ J$

(e)

Potential energy at the final height is given as:

$P_f=mgh_f=3.18\times 9.8\times 0=0\ J$

Therefore, final potential energy is 0 J.

(f)

Total mechanical energy is a constant and doesn't depend on the height.

So, total mechanical energy at 0 m is same as that at 26.6 m.

Total mechanical energy is 828.96 J.

8 0

4 years ago

*PLEASE HURRY ITS FOR A QUIZ*

PLEASE HURRY ITS FOR A QUIZ