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posledela
3 years ago
9

The highest barrier that a projectile can clear is 19.7 m, when the projectile is launched at an angle of 15.0o above the horizo

ntal. What is the projectile’s launch speed?
Physics
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

76 m /s

Explanation:

maximum height, H = 19.7 m

Angle of projection, θ = 15 degree

Let u be the projectile launch speed

Use the formula of maximum height

H = u^{2}Sin\theta ^{2}/2g

19.7 = u^{2}Sin^{2}15/19.6

u = 75.9199 = 76 m /s

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ICE Princess25 [194]
Denser materials tend to be closer to earths center due to their mass gravity is shown by the equation mg
Which stands for mass x gravity.
5 0
3 years ago
. A block of mass 4.0 kg on a spring has displacement as a function of time given by, x (t) = (1.0 cm) cos [(2.0 rad/s) t + 0.25
svlad2 [7]

Answer and Explanation:

1. Evaluate the function x(t) at t=0.5

x(t)=1cos(2t+0.25)\\x(0.5)=cos(2*0.5+0.25)=cos(1+0.25)=cos(1.25)=0.3153223624\approx0.31cm

2. The period of motion T can be calculated as:

T=\frac{2\pi}{\omega}

Where:

\omega=2rad/s

So:

T=\frac{2\pi}{2}=\pi\approx3.14s

3. The angular frequency can be expressed as:

\omega=\sqrt{\frac{k}{m} }

Solving for k:

k=(\omega)^2*m=(2)^2*4=4*4=16\frac{N}{m}

4. Find the derivate of x(t):

\frac{dx}{dt} =v(t)=-2sin(2t+0.25)

Now, the sine function reach its maximum value at π/2 so:

2t+025=\frac{\pi}{2}

Solving for t:

t=\frac{\frac{\pi}{2} -0.25}{2} =0.6603981634s

Evaluating v(t) for 0.6603981634:

v(0.6603981634)=-2sin(2*0.6603981634+0.25)=-2sin(\frac{\pi}{2} )=-2*1=2

So the maximum speed of the block is:

v(0.6603981634)=2cm/s=0.02m/s

In the negative direction of x-axis

5. The force is given by:

F=kx

The cosine function reach its maximum value at 2π so:

2t+0.25=2\pi

Solving for t:

t=\frac{2\pi-0.25}{2} =3.016592654s

Evaluating x(t) for 3.016592654:

x(3.016592654)=cos(2*3.016592654+0.25)=cos(2\pi)=1cm=0.01m

Therefore the the maximum force on the block is:

F=16*0.01=0.16N

6 0
3 years ago
Explain why stars are unevenly distributed throughout the universe.
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Stars are not spread uniformly across the universe but are normally grouped into galaxies along with interstellar gas and dust. A typical galaxy contains hundreds of billions of stars and there are more than 2 trillion galaxies
8 0
2 years ago
Why neon is in the same group as helium?
guajiro [1.7K]
Neon and helium are both gases that fall under the Noble Gases section in the periodic table of elements.

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5 0
3 years ago
Bambi is walking along the train tracks when he suddenly notices a fast approaching train and freezes in his tracks like a deer
Dmitrij [34]

Answer:

The final speed of the train and Bambi after collision is 7.44 m/s

Explanation:

Given;

mass of the train, m₁ = 1000kg

mass of  Bambi, m₂ = 75kg

initial speed of the train, u₁ =  8 m/s

initial speed of Bambi, u₂ =  0 m/s

If Bambi gets stuck to the front of the train, then the collision is inelastic.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

v is the final speed of the train and Bambi after collision

Substitute the given values and solve for v

1000 x 8 + 75 x 0 = v (1000 + 75)

8000 = v (1075)

v = 8000/1075

v = 7.44 m/s

Therefore, the final speed of the train and Bambi after collision is 7.44 m/s

8 0
3 years ago
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