Question

The highest barrier that a projectile can clear is 19.7 m, when the projectile is launched at an angle of 15.0o above the horizontal. What is the projectile’s launch speed?

Answer 1

Answer:

76 m /s

Explanation:

maximum height, H = 19.7 m

Angle of projection, θ = 15 degree

Let u be the projectile launch speed

Use the formula of maximum height

$H = u^{2}Sin\theta ^{2}/2g$

$19.7 = u^{2}Sin^{2}15/19.6$

u = 75.9199 = 76 m /s