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3 years ago

How is constant acceleration indicated on a motion map?

Physics

2 answers:

sasho [114]3 years ago

6 0

<span>by vectors that are all the same length

</span>

saw5 [17]3 years ago

6 0

Answer;

By vectors that are all the same length

Explanation;

A motion map represents the position, velocity, and acceleration of an object at various clock readings.The objects's velocity is represented by a vector.

Constant Acceleration is when the velocity of an object changes its speed uniformly.

Motion with constant acceleration occurs in everyday life whenever an object is dropped: the object moves downward with the constant acceleration 9.81 m/s², under the influence of gravity.

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A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travel

Misha Larkins [42]

Explanation:

Consider the kinematic equation,

$x = vt + \frac{1}{2} a {t}^{2}$

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

$x = 3(1.8) + \frac{1}{2} (9.3) {1.8}^{2}$

through simple algebra we get

$x = 20.466$

where this is the distance traveled in meters.

4 0

3 years ago

Simplified. The absorption spectra of ions have been used to identify the presence of the elements in the atmospheres of the sun

Nookie1986 [14]

Answer:

The answer is " $3.83 \times 10^9 \ m$ "

Explanation:

Z=2, so the equation is $E= \frac{-4B}{n^2}$

Calculate the value for E when:

n=2 and n=9

The energy is the difference in transformation, name the energy delta E Deduct these two energies

In this transition, the wavelength of the photon emitted is:

$\Delta E=2.18 \times 10^{-18} ( \frac{1}{4}- \frac{1}{81})$

$\lambda = \frac{h c}{\Delta E}$

$h ( Planck's\ constant) = 6.62 \times 10^{(-34)} \ Js \\\\ speed \ of \ light = 3 \times 10^{8} \ \frac{m}{s}\\\\= \frac{6.62 \times 10^{(-34)} \times 3 \times 10^ {8}}{2.18 \times 10^{-18}} (\frac{1}{4}- \frac{1}{81}) \\\\=3.83 \times 10^9 \ m\\\\$

6 0

3 years ago

Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bu

MArishka [77]

Complete Question:

Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bury itself just below the surface. What would have to be the mass of this asteroid, in terms of the earth’s mass M, for the day to become 25.0% longer than it presently is as a result of the collision? Assume that the asteroid is very small compared to the earth and that the earth is uniform throughout.

Answer:

m = 0.001 M

For the whole process check the following page: https://www.slader.com/discussion/question/suppose-that-an-asteroid-traveling-straight-toward-the-center-of-the-earth-were-to-collide-with-our/

6 0

3 years ago

A sack of groceries with a mas of 22 kg is lifted off the floor with a velocity of 6 m/s. What is the kinetic energy of the sack

AnnyKZ [126]

the answer is 396 joules :D

5 0

3 years ago

An archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s2 to reach a speed of 50.0 m/s as it left the bow.

laila [671]

Answer:

300 N

Explanation:

The net force acting on the arrow is given by Newton's Second Law:

$F=ma$

where

m = 0.06 kg is the mass of the arrow

a = 5,000 m/s^2 is the acceleration of the arrow

Substituting the numbers into the equation, we find

$F=(0.06 kg)(5,000 m/s^2)=300 N$

7 0

3 years ago