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Cerrena [4.2K]
2 years ago
7

How is constant acceleration indicated on a motion map?

Physics
2 answers:
sasho [114]2 years ago
6 0
<span>by vectors that are all the same length

</span>
saw5 [17]2 years ago
6 0

Answer;

By vectors that are all the same length

Explanation;

A motion map represents the position, velocity, and acceleration of an object at various clock readings.The objects's velocity is represented by a vector.

Constant Acceleration is when the velocity of an object changes its speed uniformly.

Motion with constant acceleration occurs in everyday life whenever an object is dropped: the object moves downward with the constant acceleration 9.81 m/s², under the influence of gravity.

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A car speed off around a bend at a constant 10m/s explain why it's velocity is not constant
VARVARA [1.3K]
It's velocity is not constant as direction is changing.
 
We know, velocity is speed with direction, so if direction is changing, velocity can't be constant, doesn't matter that speed is constant.

Hope this helps!
8 0
3 years ago
Could a mixture be made up of only elements and no compounds?
Nataly [62]
Yah isnt that obvious? Gasses mix everywhere in all proportions.
7 0
3 years ago
Read 2 more answers
Each plate of a parallel‑plate capacitor is a square of side 3.63 cm, and the plates are separated by 0.473 mm. The capacitor is
NARA [144]

Answer:

E= 55.53 x 10³ V/m

Explanation:

Given that

a=  3.63 cm

Area ,A= a²

distance ,d= 0.473 mm

Stored energy ,U = 8.49 nJ

Value of capacitor given as

C=\dfrac{\varepsilon _oA}{d}

By putting the values

C=\dfrac{8.85\times 10^{-12}\times 3.63^2\times 10^{-4}}{0.473\times 10^{-3}}

C=2.46 x 10⁻¹¹ F

U=\dfrac{1}{2}CV^2

V=Voltage difference

V=\sqrt{\dfrac{2U}{C}}

V=\sqrt{\dfrac{2\times 8.49\times 10^{-9}}{2.46\times 10^{-11}}}

V=26.27 V

V= E d

E=Electric filed

26.27 = E x 0.473 x 10⁻³

E= 55.53 x 10³ V/m

7 0
3 years ago
In this model, the velocity of the spacecraft at position 2 is the velocity of the craft at position 4. at position 1, the direc
Free_Kalibri [48]

1. The velocity of the spacecraft at position 2 is greater than the velocity of the craft at position 4.

This is due the gravity field of the Earth is used to accelerate the craft. This is true when in a specific point the direction of the movement of the craft is the same direction of the movement of the planet.

In this case the craft will be “catched” by the Earth’s gravitational field, making the craft  to enter a circular orbit.

2. At point 1, the direction of the spacecraft changes because of the gravitational force between earth and the spacecraft.

As explained in the first answer, this is the exact point where the trajectory of the spacecraft enters into a circular orbit because of the attraction due gravity of the Earth and therefore changes its direction.

3. Position 3 represents the orbital path of Earth

Being this the orbital path of the Earth and considering the trajectory of the craft, the condition of accelerating the craft is accomplished. If the orbital path of the Earth were the opposite, the effect on the craft would be braking.

Note all of these is related to the gravitational assistance, this consists in a maneuver in which the energy of the gravitational field of a planet or satellite is used to obtain an acceleration or braking of the probe or craft, changing its trajectory.

To learn more about velocity of the spacecraft : brainly.com/question/11900446

#SPJ4

7 0
11 months ago
1. What is the difference between longitudinal and transverse waves? Compare and contrast
Anvisha [2.4K]

Answer: image to much to type.

Explanation:

8 0
3 years ago
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