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wariber [46]
3 years ago
7

11

Physics
1 answer:
GarryVolchara [31]3 years ago
7 0

Explanation:

Given that,

The pilot directs the aircraft to fly due north at 600km/h.

A side-wind blows at  100km/h towards the east.

We need to find the aircraft's resultant velocity. et it be v. It can be calculated as follows :

v=\sqrt{600^2+100^2} \\\\v=608.27\ m/s

For direction,

\tan\theta=\dfrac{600}{100}\\\\\tan\theta=6\\\\\theta=\tan^{-1}(6)\\\\\theta=80.53^{\circ}

So, the aircraft's resultant velocity is 608.27 km/h and it is at and angle of 80.53°.

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1 point
Darya [45]

Given that,

Mass of object, m = 55 kg

Mechanical energy of the object, M = 4306 J    

Potential energy, P = 2940 J

We know that the mechanical energy is the sum of kinetic and potential energy such that,

Mechanical energy = kinetic energy + potential energy

K=M-P\\\\K=4306-2940\\\\K=1366\ J

Kinetic energy is given by :

K=\dfrac{1}{2}mv^2v is velocity of object

v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 1366}{55}} \\\\v=7.04\ m/s

So, the velocity of object is 7.04 m/s.            

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