V = f x lamda
Wave speed = frequency x wavelength
2x1 = 2 so wave speed = 2m/s
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Acceleration is equal to velocity final minus velocity initial divided by time. 6m/s minus 4m/s divided by 5 seconds is 0.4m/s^2.
Answer:
46°C
Explanation:
q = mCΔT
336,000 J = (20 kg) (4200 J/kg/°C) (50°C − T)
T = 46°C
Answer:
Acceleration of the bags is 0.861 m/s²
Explanation:
Given:
Mass of the rock, m = 22.5 kg = mass of the food
Slope, Θ = 55.5°
Now, from the figure, we have
T - mgsinΘ = ma ...................(1)
'a' is the acceleration of the mass
where T is the tension
also for the second mass, we have
mg - T = ma
now substituting the value of T from the equation (1) we get
mg - (ma + mgsinΘ) = ma
or
mg(1 - sinΘ) = (m + m)a
or
a = 
on substituting the values we get
a = 
or
a = 0.861 m/s²
Hence, the acceleration of the bags is 0.861 m/s²