r = radius of the circle traveled by the particle = 76 cm = 0.76 m
T = time period of revolution for the particle = 4.5 s
w = angular velocity of the particle
angular velocity of the particle is given as
w = 2π/T
inserting the values
w = 2 (3.14)/4.5
w = 1.4 rad/s
a = centripetal acceleration of the particle in the circle
centripetal acceleration is given as
a = r w²
inserting the values
a = (0.76) (1.4)²
a = 1.5 m/s²
C Weight is the gravitational pull on an object
In statistics there are different types of distributions, like rectangular, or Poisson, A normal distribution is bellshaped
Answer: 2 s
Explanation: In order to solve this problem we have to use the formule of the final speed getting with a constant acceleration, it is given by;
Vfinal=Vo+a*t where Vo is zero.
so then t=Vfinal/a = (10 m/s)/5 m/s^2= 2 s
