Answer:
Major Product = 4-chloro-4-methylcyclohex-1-ene
Explanation:
Alkene are the class of organic compounds which contain one or more double bonds between two carbon atoms. Alkenes are considered most reactive among the unsaturated hydrocarbons and they undergo <em>addition reactions</em> due to high electron density around the double bonds.
In given question it is written that we are provided with one equivalent of HCl while, our compound contains two double bonds (diene) so in selected starting material the HCl will be added across (hydrohalogenation reaction) the substituted double bond because it will give a more stable carbocation (<u><em>tertiary carbocation</em></u>) during the reaction course. Hence, as shown in reaction scheme 4-chloro-4-methylcyclohex-1-ene will be the major product.
Since greenhouses are designed to trap in heat, we call global warming the “greenhouse effect” because it essentially does the same thing. “Greenhouse” gases (gases that easily trap heat) clog up the outer layers of the atmosphere and prevents heat from leaving the planet. The gases trap heat, just like greenhouses.
YES, the arrangement of elements on the periodic table relate to their chemical properties
Explanation:
As you move across a period, the atomic radius decreases due to the increase in atomic mass and hence attraction of orbitals by the increasingly positive nucleus. Therefore, the atoms become increasingly harder to lose electrons (due to increasing ionization energy) in their valence shell and more likely to take up electrons in chemical reactions.
The lower you go down the periodic table the higher the reactivity of the atoms. This is because they have more electron shells and the valence electrons are shielded from the atomic nuclei by underlying orbitals. This means that the valence electrons are easily lost (ionization energy is low) and can, therefore, react fast in chemical reactions.
Learn More:
For more on the periodic table check out;
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Hey there!
No of hybrid orbitals , H = ( V +S - C + A ) / 2
Where H = no . of hybrid orbitals
V = Valence of the central atom = 5
S = No . of single valency atoms = 4
C = No . of cations = 1
A = No . of anions = 0
For PCl4 +
Plug the values we get H = ( 5+4-1+0) / 2
H = 4 ---> sp3 hybridization
sp3 hybrid orbitals are used by phosphorous in the PCl4+ cations
Answer C
Hope that helps!
