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3 years ago

What causes the pressure that allows diamonds to form in the mantle?

Physics

1 answer:

erik [133]3 years ago

8 0

Answer:

Diamonds are formed in Mantle and they require large amount of temperature and pressure for their formation. These come up in higher layers due to volcanic eruptions. The pressure is caused by the downward force from the rocks in the crust

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How do you convert from picoseconds to milliseconds using the conversion factors?

andrew11 [14]

There are 10⁹ picoseconds in 1 Ms

1 picosecond= 10¹² s

1 Ms = 10⁻³ s

so the number of picoseconds in one Ms=(10⁻³ s/1 Ms) * (10¹² Ps/ 1 s)=10⁹

Thus there are 10⁹ picoseconds in 1 Ms

8 0

3 years ago

Which is the BEST example of the kind of mechanics that are studied in sports biometrics?

ikadub [295]

Answer:

-A.

Explanation:

: Hope it's Help:

[correct me if I'm not correct]

5 0

2 years ago

Practice entering numbers that include a power of 10 by entering the diameter of a hydrogen atom in its ground state, dH = 1.06

Slav-nsk [51]

Answer:

$1.06085\times 10^{-10}\ m$

Explanation:

h = Planck's constant = $6.626\times 10^{-34}\ m^2kg/s$

m = Mass of electron = $9.11\times 10^{-31}\ kg$

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

e = Charge of electron = $1.6\times 10^{-19}\ C$

n = 1 (ground state)

Angular momentum is given by

$L=mvr$

From Bohr's atomic model we have

$L=\dfrac{nh}{2\pi}$

$mvr=\dfrac{nh}{2\pi}\\\Rightarrow v=\dfrac{nh}{2\pi mr}$

The centripetal force will balance the electrostatic force

$\dfrac{ke^2}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow \dfrac{ke^2}{r}=mv^2\\\Rightarrow \dfrac{ke^2}{r}=m(\dfrac{nh}{2\pi mr})^2\\\Rightarrow r=\dfrac{n^2h^2}{4\pi^2mke^2}\\\Rightarrow r=\dfrac{1^2\times (6.626\times 10^{-34})^2}{4\pi^2 \times 9.11\times 10^{-31}\times 8.99\times 10^{9}\times (1.6\times 10^{-19})^2}\\\Rightarrow r=5.30426\times 10^{-11}\ m$

The diameter is $2\times 5.30426\times 10^{-11}=1.06085\times 10^{-10}\ m$

7 0

3 years ago

It took a bulldozer 62,000 J of work to move a rock 30 m. It took 5 minutes. How much force did the bulldozer have to apply?

NeX [460]

Answer:

A (2066,6 N)

Explanation:

Use the Work formula

62.000J = F . 30

62.000/30 = 2066,6 N

The amout of time it took to move the rock doesn´t matter at all.

It is called a distraction variable, We don´t need it to solve the problem it is there just to confuse.

5 0

3 years ago

Which of the following statements is untrue in regard to sound traveling in air?

maksim [4K]

Air never stops? IDK

7 0

3 years ago