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natka813 [3]
3 years ago
8

on his fishing trip Justine takes the boat 12 km south. The fish aren't biting so he goes 4 km west. He follows a school of fish

1 km north. What distance did he cover? What was his displacement?
Physics
1 answer:
Umnica [9.8K]3 years ago
4 0
[ Please make a chart by following the directions on your own, 'cause it's hard to explain, here (only directions), magnitudes and answers are here ] :

Distance = 12 + 4+ 1 = 17 Km
[Just add all the values ]

Displacement, Now, if you'll look at your triangle, which has formed by his directions, perpendicular is 11, base is 4, & you need to calculate that hypotenuse which is your displacement.

So, apply Pythagoras Theorem here:
H² = P² + B²
H² = 11² + 4²
H²= 121 + 16
H = √137= 11.70 Km

In short, Distance = 17 Km and Displacement = 11.70 Km

Hope this helps!
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A kangaroo jumps straight up to a vertical height of 1.45 m. How long was it in the air before returning to Earth?
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Answer:

1.08 s

Explanation:

From the question given above, the following data were obtained:

Height (h) reached = 1.45 m

Time of flight (T) =?

Next, we shall determine the time taken for the kangaroo to return from the height of 1.45 m. This can be obtained as follow:

Height (h) = 1.45 m

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1.45 = ½ × 9.8 × t²

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Take the square root of both side

t = √(1.45/4.9)

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T = 1.08 s

Therefore, it will take the kangaroo 1.08 s to return to the earth.

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