The reaction is:
So for every molecule of nitrogen we need 3 molecules of hydrogen.
Now, we have 4 molecules of nitrgen, so if the total amount of nitrogen react we would need 4x3=12 molecules of hydrogen.
We know that there are only 9 molecules of hydrogen present, so it is not possible that all the nitrogen present react. Therefore the limiting reactant is hydrogen.
To answer how many molecules of ammonia (NH3) are produced we need to calculate the amount formed if all the hydrogen present reacts:
For every 3 molecules of hydrogen 2 molecules of ammonia are formed, so for 9 molecules of hydrogen the molecules of ammonia formed are: 2x3=6.
To form 6 molecules of ammonia there are needed 6/2=3 molecules of nitrogen, so only one remains after the reaction.
To summerize:
• The number of molecules of ammonia formed are 6
,
• The limiting reactant is hydrogen
,
• The number of molecules remaining after the reaction are:
molecules of hydrogen: 0
molecules of nytrogen: 1
Notice that each reactant is made up of two elements. To predict the products, all you have to do is interchange the combination of the two reactants while taking note that metal comes first, followed by nonmetals. With that being said, the reaction would be:
CaC₂ + 2 H₂O --> C₂H₂ + Ca(OH)₂
<em>So, the answer is C₂H₂.</em>
A voltaic cell operates such that the ions move from the negative electrode to the positive electrode.The negative electrode is the cathode while the positive electrode is the anode. This is in reverse to the cation-anion nomenclature. Hence, the answer to this problem is choice 2.
The chemical formula for this is KNO₃ (that small number is a 3)
hope this helps and if it needs to be broken down further then let me know :)
Answer:
Na2SO4
Explanation:
In the crisscross method, we can write the correct formula for an ionic compound by crossing over the numerical value of each of the ion charges to now serve as the subscript of the oppositely charged ion. Subsequently, the signs of the charges are dropped and the correct formula of the ionic substance is obtained.
For sodium sulphate;
Na ^+ SO4^2-
By crisscrossing and dropping the signs to obtain the subscripts we now have;
Na2SO4
