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devlian [24]
3 years ago
9

Referring to an activity series, which of the following combinations of reactants would not produce a successful single-replacem

ent reaction?
A) Li + NaCl
B) Cu + CaCl2
C) Mg + FeCl3
D) Ca + AlCl3
Chemistry
2 answers:
Rom4ik [11]3 years ago
6 0
B) Cu + CaCl2
hope it helps
ElenaW [278]3 years ago
3 0

Answer:

Cu + CaCl₂ would not produce a successful single replacement reaction.

Explanation:

Activity series is constructed on the basis of tendency of an element to lose or gain electrons.

An element which can reduced other can replace it from the ionic solution.

More the reactivity of the metal more the tendency to replace others.

The tendency is measured in terms of standard reduction potential, lower the reduction potential more the tendency to replace other (a better reducing agetn).

A) Li + NaCl, here Li is a better reducing agent so can replace sodium.

B) Cu + CaCl₂, here Ca is a better reducing agent so copper cannot replace calcium.

C) Mg + FeCl₃, Mg is a better reducing agent so can replace iron.

D) Ca + FeCl₃, Ca Mg is a better reducing agent so can replace iron.

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zvonat [6]
Gravity is the force that keeps the planets in orbit.
4 0
3 years ago
Read 2 more answers
PLEASE HELP ME I NEED HELP
Crazy boy [7]

Answer:

<u>5 moles S x (36.02 g S/mole S) = 180.1 grams of S</u>

Explanation:

The periodic table has mass units for every element that can be correlated with the number of atoms of that element.  The relationship is known as Avogadro's Number.  This number, 6.02x10^{23} , is nicknamed the mole, which scientists found to be a lot more catchy, and easier to write than  6.02x10^{23}.  <u>The mole is correlated to the atomic mass of that element.</u>  The atomic mass of sulfur, S, is 36.02 AMU, atomic mass units.  <u>But it can also be read as 36.02 grams/mole.</u>

<u></u>

<u>This means that 36.02 grams of S contains 1 mole (6.02x</u>10^{23}<u>) of S atoms</u>.

<u></u>

This relationship holds for all the elements.  Zinc, Zn, has an atomic mass of 65.38 AMU, so it has a "molar mass" of 65.38 grams/mole.  ^5.38 grams of Zn contains 1 mole of Zn atoms.  

And so on.

5.0 moles of Sulfur would therefore contain:

(5.0 moles S)*(36.02 grams/mole S) = <u>180.1 grams of S</u>

Note how the units cancel to leaves just grams.  The units are extremely helpful in mole calculations to insure the correct mathematical operation is done.  To find the number of moles in 70 g of S, for example, we would write:

(70g S)/(36.02 grams S/mole S) = 1.94 moles of S.  [<u>Note how the units cancel to leave just moles</u>]

4 0
2 years ago
3. If the percent by volume is 2.0% and the volume of solution is 250 mL, what is the volume of solute in solution? (1 point) 0.
igor_vitrenko [27]
Volume percent = Volume of solute
                              ----------------------------------
                                Volume of the solution
  
                  2                    Volume of the solute
               -------   =           ------------------------------
                100                               250
                     
         Volume of the solute = 2 x 250
                                                ------------
                                                  100         

                                             =   5 mL.

Hope this helps!




                            




4 0
3 years ago
What force pulls electrons and protons together?
ruslelena [56]
Electrostatic force ..
7 0
3 years ago
The second-order rate constants for the reaction of oxygen atoms witharomatic hydrocarbons have been measured (R. Atkinson and J
Pepsi [2]

Answer:

A = 1,13x10¹⁰

Ea = 16,7 kJ/mol

Explanation:

Using Arrhenius law:

ln k = -Ea/R × 1/T + ln(A)

You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).

Using the values you will obtain:

y = -2006,9 x +23,147

As R = 8,314472x10⁻³ kJ/molK:

-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹

<em>Ea = 16,7 kJ/mol</em>

Pre-exponential factor is:

ln A = 23,147

A = e^23,147

<em>A = 1,13x10¹⁰</em>

<em></em>

I hope it helps!

6 0
3 years ago
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