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taurus [48]
3 years ago
7

What is the normality of a solution prepared by dissolving 75.0 g citric acid, a triprotic acid with molar mass of 192.14 g, in

water to make 250. mL solution?
a. 0.0576 N
b. 0.293 N
c. 4.68 N
d. 0.173 N
e. 1.56 N
Chemistry
1 answer:
Mademuasel [1]3 years ago
5 0
It’s C. 4.68 N

I hope this helped out! Have a nice day :)
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If you have 10cm of snow with a volume of 40mL and a density of 0.5 g/mL how many inches of rain is this?
Lelu [443]

Density is the mass of compound divided by its volume can be shown as follows:

d = 0.5 g /mL = m /V = m /40 = 0.5

m = 20 g

40 mL of snow having 20 g of mass calculated from density.

Now, 10 cm of snow = 3.93 inches = 20 g  

As, 10 inches of rain will produce 11 inches of ice as the volume of ice is bigger than rain water.

10 inches rain = 11 inches snow

3.93 inches of snow produced by  

= (3.93 * 10) /11 = 3.57 inches rain.

Thus, 3.57 incehs of rain produces by 10 cm snow.

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3 years ago
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Suppose that a certain fortunate person has a net worth of $77.0 billion ($). If her stock has a good year and gains $3.20 billi
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Answer:

New net worth to three significant figures = $80.2 billion

Dollars are given to charity = $100,250,000

Explanation:

Net worth = $77.0 billion

stock Gains = $3.20 billion

New net worth = $77.0 billion + $3.20 billion = $80.20 billion

New net worth to three significant figures = $80.2 billion

One-eighth of a percent = (1/8 x 1) / 100 = 0.00125

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3 years ago
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Answer:

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Explanation:

<u>Calculating number of moles</u>

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<u>At STP</u>

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2 years ago
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