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Answer:
T₂ = 669.2 K
Explanation:
Given data:
Initial pressure = 660 torr
Initial temperature = 26 °C (26 +273 = 299 K)
Final volume = 280 mL ( 280/1000 = 0.28 L)
Final pressure = 940.0 torr
Final volume = 0.44 L
Final temperature = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁ /P₁V₁
T₂ = 940 torr × 0.44 L × 299 K / 660 torr × 0.28 L
T₂ = 123666. 4 torr. L. K / 184.8 torr. L
T₂ = 669.2 K
- The density of the mineral fragment is
(20.47 g/cm3).
- Density can be regarded as<em> ratio of mass to the volume </em>of the object.
Density = (mass/ volume)
Given:
volume of mineral fragments= 2.57 cm3
mass = 52.6 g
density of the mineral fragment = (52.6/2.57)
= 20.47 g/cm3
- Therefore, density of the mineral fragment is (20.47 g/cm3)
Learn more at: brainly.com/question/13594966
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