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FromTheMoon [43]
3 years ago
7

According to the periodic table of the elements which element is most similar to magnesium

Chemistry
1 answer:
dangina [55]3 years ago
6 0
Calcium. Elements in the same group (vertical column of the periodic table) have similar properties because they share the same number of valence electrons.
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When writing a formula for a compound having a transition metal in it, _____.
Stella [2.4K]

Answer:

it is always necessary to use the roman numeral as the assigned charge of the metal.

Explanation:

This is so that one would know which Transition metal is being used. For example copper (II) would be Cu²+

3 0
3 years ago
A 265-mL flask contains pure helium at a pressure of 751 torrs. A second flask with a volume of 465 mL contains pure argon at a
Nadya [2.5K]

Answer:

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

Explanation:

Step 1: Data given

Volume of the flask helium = 265 mL

Pressure in the helium flask = 751 torr = 751/760 atm

Volume of the flask argon = 465 mL

Pressure in the argon flask = 727 torr = 727/760 atm

The total pressure exerted by a gaseous mixture is equal to the sum of the partial pressures of each individual component in a gas mixture.

Step 2: Calculate total volume

Total volume = 265 mL + 465 mL = 730 mL =  0.730 L

Step 3: Boyle's Law:

P1V1=P2V2

⇒ with P1 = total pressure gas exerts in its own flask

 ⇒ with V1 = volume of flask with stopcock valve closed

 ⇒ with P2 = partial pressure of gas exerts on total volume of both flasks when stopcock valve is opened  

 ⇒ with V2 = total volume of both flasks with stopcock valve opened

Helium using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of helium = 751 /760 = 0.98816 atm

 ⇒ with V1 = volume of helium = 0.265 L

 ⇒ with P2 = The new partial pressure of helium

 ⇒ with V2 = total volume = 0.730 L

(0.98816 atm)(0.265L)=P2(0.730L)

P2=0.359 atm

Argon using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of argon = 727/760 = 0.95658 atm

 ⇒ with V1 = volume of argon = 0.465 L

 ⇒ with P2 = The new partial pressure of argon

 ⇒ with V2 = total volume = 0.730 L

(0.95658 atm)(0.465L)=P2(0.730L)

P2=0.609 atm

Step 4: Convert pressure in atm to torr

Pressure helium = 0.359 atm = 272.8 torr

Pressure argon = 0.609 atm = 472.8 torr

Step 5: Calculate Total pressure

Ptotal = P(He)+P(Ar)

⇒ Pt  = total pressure of the gas mixture

⇒ P(He) = partial pressure of Helium

 ⇒ P(Ar)  = partial pressure of Argon

Pt = 272.8 torr + 472.8 torr

Pt = 745.6 torr

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

5 0
3 years ago
How many moles of KClO3 reacted if 9 moles of O2 were produced in this reaction: 2KClO3 → 2KCl + 3O2
kherson [118]
2 mol KClO₃ - 3 mol O₂
x mol KClO₃ - 9 mol O₂

x=9*2/3= 6 mol
3 0
3 years ago
A 7.5 L cylinder contains 5 moles of gas at a temperature of 274°C. What is its pressure in kiloPascals (kPa)?
AleksAgata [21]
<h3><u>Answer;</u></h3>

 = 3032.15 kPa

<h3><u>Explanation;</u></h3>

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Volume = 7.5 L, T = 274 +273 = 547 K, N = 5 moles

Therefore;

Pressure = nRT/V

               = (5 × 0.08206 × 547)/7.5 L

               = 29.925 atm

But; 1 atm = 101325 pascals

Hence; Pressure = 3032150.63 pascals

                            <u>= 3032.15 kPa</u>

               

3 0
3 years ago
What is the ion #for lodine (l)?
AveGali [126]

Answer:An iodide ion is the ion I−. Compounds with iodine in formal oxidation state −1 are called iodides. This page is for the iodide ion and its salts, not organo iodine compounds. In everyday life, iodide is most commonly encountered as a component of iodized salt, which many governments mandate.

brainliest pls

5 0
3 years ago
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