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3 years ago

Convection only occurs in what? a. gases b. fluids c. liquids d. solids

Physics

2 answers:

Butoxors [25]3 years ago

7 0

the answer on edginuity is B- Fluids (i just took the test)

vekshin13 years ago

3 0

Answer:

b. Fluids

Explanation:

Convection is one of the three methods of transfer of heat. Let's define them all:

- Conduction: conduction occurs when two objects (or two substances) are in contact with each other; heat is transferred from the warmer object to the colder object by the collisions between the particles of the warmer object (which have on average greater kinetic energy) and the particles of the colder object (which have on average smaller kinetic energy). This type of heat transfer can occur in solids, liquids and gases.

- Convection: convection occurs when there is a fluid which is heated from a heat source. As the part of the fluid closer to the heat source becomes warmer, it becomes less dense and it expands, rising and being replaced by the part of the fluid which is colder. Then, the mechanism continues, generating a convection current (like a cycle) which transport the heat over the whole fluid. This method of heat transfer occurs in fluids (liquids and gases) only.

- Radiation: radiation occurs when heat is carried by electromagnetic waves (which transport energy, so also heat, through space). Radiation can occur in any medium, and can also occur in vacuum since electromagnetic waves can travel in vacuum as well.

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What is the difference between a partial and total lunar eclipse?

storchak [24]

Answer:

During a total lunar eclipse, the moon and sun are on the exact opposite sides of the Earth, leaving the moon entirely in the Earth's shadow. During a partial lunar eclipse, only part of the moon is in the Earth's shadow.

Explanation:

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2 years ago

How many electrons are in the element that comes just before platinum in the periodic table?

laila [671]

The element is iridium and it has 77 electrons

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3 years ago

2. At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (nautical miles per hour; a n

AleksandrR [38]

Answer:

Explanation:

Let the reference origin be location of ship B in the beginning. We can then create the equation of motion for ship A and ship B in term of time t (hour):

A = 12 - 12t

B = 9t

Since the 2 ship motions are perpendicular with each other, we can calculate the distance between 2 ships in term of t

$d = \sqrt{A^2 + B^2} = \sqrt{(12 - 12t)^2 + (9t)^2}$

For the ships to sight each other, distance must be 5 or smaller

$d \leq 5$

$\sqrt{(12 - 12t)^2 + (9t)^2} \leq 5$

$(12 - 12t)^2 + (9t)^2 \leq 25$

$144t^2 - 288t + 144 + 81t^2 - 25 \leq 0$

$225t^2 - 288t + 119 \leq 0$

$(15t)^2 - (2*15*9.6)t + 9.6^2 + 26.84 \leq 0$

$(15t^2 - 9.6)^2 + 26.84 \leq 0$

Since $(15t^2 - 9.6)^2 \geq 0$ then

$(15t^2 - 9.6)^2 + 26.84 > 0$

So our equation has no solution, the answer is no, the 2 ships never sight each other.

8 0

3 years ago

20 points+ Brainliest

Helen [10]

Answer:

The answer is B. hope this helps

Explanation:

3 0

3 years ago

An electron is projected with an initial speed of 5 3.2 10 / ⋅ m s directly toward a proton that is fixed in place. If the elect

Dvinal [7]

Answer:

The distance is $d =1.66*10^{-9}m$

Explanation:

From the question we are told that

The initial speed of the electron is $v_i = 3.2 *10^5 m/s$

The mass of electron is $m = 9.11*10^{-31}kg$

Let $d$ be the distance between the electron and the proton when the speed of the electron instantaneously equal to twice the initial value

Let $KE_i$ be the initial kinetic energy of the electron \

Let $KE_d$ be the kinetic energy of the electron at the distance $d$ from the proton

Considering that energy is conserved,

The energy at the initial position of the electron = The energy at the final position of the electron

i.e

$KE_i +U_1 = KE_d + U_2$

$U_1 \ and \ U_2$ are the potential energy at the initial position of the electron and at distance d of the electron to the proton

Here $U_1 = 0$

So the equation becomes

$\frac{1}{2} mv_i^2 = \frac{1}{2} mv_d^2 + \frac{kq_1 q_2}{d}$

Here $q_1 \ and \ q_2$ are the charge on the electron and the proton and their are the same since a charge on an electron is equal to charge on a proton