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Lelu [443]
3 years ago
15

The water in a lake is at 5 °C. A diver measures the pressure of the water at two different depths in the lake. He repeats the m

easurements on a different day when the water is at 15°C. The density of the water decreases when its temperature increases. Which combination of depth and temperature produces the greatest water pressure?
Physics
1 answer:
Dmitrij [34]3 years ago
3 0

The combination of depth at 10 m and the temperature of 15 °C will produce the greatest water pressure.

Explanation:

The pressure in any liquid is directly proportional to the depth of the water body. This is because, the more the depth, the more the buoyant force will be acting on the liquid surface. So if the water is kept constant at 15 °C, the volume is said to increase with increase in temperature as volume is directly proportional to the temperature. The same goes for pressure, the pressure of liquid increases with increase in temperature. So the combination of depth at 10 m and the temperature of 15 °C will produce the greatest water pressure.

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An eagle flying at 15 m/s has 600 J of kinetic energy. About how much is the eagles mass?
Eduardwww [97]

Answer:

5.33kg

Explanation:

Given parameters:

Velocity of eagle  = 15m/s

Kinetic energy of the eagle = 600J

Unknown:

Mass of the eagle  = ?

Solution:

The kinetic energy of any body is the energy due to the motion of a body. There are different forms of kinetic energy some of which are thermal, mechanical, electrical  energy.

The formula of kinetic energy is given as;

              Kinetic energy  = \frac{1}{2} m v²

where m is the mass, V is the velocity

   substitute the parameters in the equation;

                       600  = \frac{1}{2} x m x 15²

                     225m  = 1200

                            m  = \frac{1200}{225}    = 5.33kg

3 0
3 years ago
What pushes against gravity in: a main sequence star, a white dwarf, a neutron star, and a black hole? electron degeneracy, neut
Inga [223]

Answer:

heat pressure, electron degeneracy, neutron degeneracy, and nothing

Explanation:

Main Sequence Star: It is a star in which nuclear fusion is happening in the core of the star. Hydrogen molecules fuse together to generate Helium. This nuclear fusion generates outward gas pressure and radiation pressure which balances the inward gravity thus creating an equilibrium which keeps the stars in shape.

White dwarf: It is the end stage of a medium sized star like the Sun. Outer layers of the star are thrown in the form a shell/bubble leaving a small and dense core in the center called as white dwarf. This core consists of carbon and oxygen. Nuclear fusion doesn't occur in the core of white dwarfs. The inward gravity is balanced by the electron degeneracy pressure. Thus these stars will keep on radiating the remaining heat and will turn in to a black dwarf at the end.

Neutron Star: This is the end stage of a supermassive star (1-3 times the mass of the Sun). At the last stage of the life the core collapses. In these stars the inward gravity is so huge that the pressure overcomes the electron degeneracy pressure and crushes together the electron and proton to form neutron. The neutron then stops the collapse and balances the inward gravity.

Black Hole: This is the end stage of a hyper massive stars weighing more than 3 times the mass of the Sun. The inward gravitational force is so huge that even the neutrons are not able to stop the collapse the core. thus the mass of the star collapses into a very small area of immense gravity. There is nothing that can balance this inward gravity.

3 0
3 years ago
A 2. 0 μf and a 4. 0 μf capacitor are connected in series across an 8. 0-v dc source. what is the charge on the 2. 0 μf capacito
Nezavi [6.7K]

voltage across 2.0μf capacitor is 5.32v

Given:

C1=2.0μf

C2=4.0μf

since two capacitors are in series there equivalent capacitance will be

[tex] \frac{1}{c} = \frac{1}{c1} + \frac{1}{c2} [/tex]

c =  \frac{c1 \times c2}{c1 + c2}

=  \frac{2 \times 4}{2 + 4}

=1.33μf

As the capacitance of a capacitor is equal to the ratio of the stored charge to the potential difference across its plates, giving: C = Q/V, thus V = Q/C as Q is constant across all series connected capacitors, therefore the individual voltage drops across each capacitor is determined by its its capacitance value.

Q=CV

given,V=8v

= 1.33 \times 10 {}^{ - 6}  \times 8

= 10.64 \times 10 {}^{ - 6}

charge on 2.0μf capacitor is

\frac{Qeq}{2 \times 10 {}^{ - 6} }

=  \frac{10.64 \times 10 {}^{ - 6} }{2 \times 10 {}^{ - 6} }

=5.32v

learn more about series capacitance from here: brainly.com/question/28166078

#SPJ4

3 0
2 years ago
Sharon the ant (Aaron’s sister) sits at the edge of a turntable of radius R that is spinning with period T. As she makes one-hal
Dmitry_Shevchenko [17]

Answer:

a = \dfrac{4\pi^2R}{T^2}

Explanation:

The acceleration of a circular motion is given by

a = \omega^2 R

where \omega is the angular velocity and R is the radius.

Angular velocity is related to the period, T, by

\omega=\dfrac{2\pi}{T}

Substitute into the previous formula.

a = (\dfrac{2\pi}{T})^2 R

a = \dfrac{4\pi^2R}{T^2}

This acceleration does not depend on the linear or angular displacement. Hence, the amount of rotation does not change it.

6 0
3 years ago
A 2 kg blue car is moving 6 m/s to the right and collides with a 3 kg red car that is moving 2 m/s to the left. The cars collide
snow_lady [41]

Answer:

Their velocity after the collision is 1.2 m/s, to the right.

Explanation:

Given;

mass of the blue car, m₁ = 2 kg

initial velocity of the blue car, u₁ = 6 m/s

mass of the red car, m₂ = 3 kg

initial velocity of the red car, u₂ = 2 m/s

let the blue car moving to the right be in positive direction

also, let the red car moving to the left be in negative direction

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ - m₂u₂ = v(m₁ + m₂)

where;

v is their velocity after the collision

(2 x 6) - (3 x 2) = v(2 + 3)

12 - 6 = 5v

6 = 5v

v = 6/5

v = 1.2 m/s, to the right

Therefore, their velocity after the collision is 1.2 m/s, to the right.

7 0
3 years ago
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