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Tpy6a [65]
4 years ago
7

Which quantity is a vector quantity?

Physics
1 answer:
torisob [31]4 years ago
4 0

A vector quantity has both magnitude and direction. In other words, it refers to a physical quantity that is defined by both magnitude and direction. Some of the examples of vectors include displacement, force, velocity, acceleration, and momentum.

<h2>Further Explanation</h2>

Practical example of a vector: the GPS (global positioning system) in your car is meant to guide you through your journey; however, the GPS will provide two sets of information that will help you get to your destination such as 500 feet and then turn left. That is a perfect example of a vector.

An arrow is used to represent a vector and it is in the same direction as the quantity and also its length is proportional to the magnitude of the quantity.

Before a quantity can be said to be a vector, it must be characterized not only by magnitude and direction but must obey some specific rules of combination, that is, it must conform to some basic rules of combination.

For example, for a quantity to be a vector, it must obey the rule of vector addition, which is symbolically expressed as A + B = C.

Therefore, force, acceleration, momentum, velocity, displacement, electromagnetic fields are all typical example of a vector quantity.

LEARN MORE:

  •  which quantity is a vector quantity  brainly.com/question/3579752
  • Which quantity is a vector quantity?  brainly.com/question/2912049

KEYWORDS:

  • vector quantity
  • acceleration
  • force
  • magnetic field
  • GPS
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A sample of an unknown substance has a mass of 0. 158 kg. If 2,510. 0 J of heat is required to heat the substance from 32. 0°C
guapka [62]

The specific heat of the unknown substance with a mass of 0.158kg is 0.5478 J/g°C

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

The specific heat capacity of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

  • Q = quantity of heat absorbed (J)
  • c = specific heat capacity (4.18 J/g°C)
  • m = mass of substance
  • ∆T = change in temperature (°C)

According to this question, 2,510.0 J of heat is required to heat the 0.158kg substance from 32.0°C to 61.0°C. The specific heat capacity can be calculated:

2510 = 158 × c × (61°C - 32°C)

2510 = 4582c

c = 2510 ÷ 4582

c = 0.5478 J/g°C

Therefore, the specific heat capacity of the unknown substance that has a mass of 0.158 kg is 0.5478 J/g°C.

Learn more about specific heat capacity at: brainly.com/question/2530523

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