We have that if the sample size is greater than 5% of the entire population, a finite population correction factor (fpc) is multiplied with the standard error :

fpc = $\sqrt{\frac{N -n}{N -1} }$

We know that N = 250 n = 91, replacing:

fpc = $\sqrt{\frac{250 - 91}{250 -1} }$

fpc = 0.799

Now, the formula would then be:

SE = $\sqrt{\frac{p * (1 -p)}{n} }$ *fpc

Now replacing, knowing that p = 0.12

SE= $\sqrt{\frac{0.12 * (1 - 0.12)}{91} }$ *0.799

SE = 0.0272

So the standard error of the proportion is 0.0272

6 0

3 years ago

James estimate the product of 48 and 53 is that reasonable

Debora [2.8K]

50 x 50= 2500.............

8 0

3 years ago

The graph shows the relationship between the number of months different students practiced baseball and the number of games they

ratelena [41]

Answer:

A) from the line of best fit, the approximately y-intercept is (0,1.8). This means without any practice, 1h.8 games are won.

B) slope: (5.6-1.8)/(2-0) = 1.9

y = 1.9x + 1.8

(Line of best fit)

x = 13,

y = 1.9(13) + 1.8 = 26.5

Predicted no. of games won after 13 months of practice is 26.5

7 0

3 years ago

Read 2 more answers

I will give brainliest

ruslelena [56]

Answer:

w is the length

Step-by-step explanation:

length squared is always the area of a square

8 0

3 years ago

Read 2 more answers