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3 years ago

Which of the following is a unit of volume of solids?

Physics

2 answers:

Verizon [17]3 years ago

6 0

Answer:

Cubic meters is the unit of volume.

Alla [95]3 years ago

4 0

Answer:

Cubic meters is the unit of volume.

Explanation:

Volume :

Volume is the multiplication of height, width and length of the solids.

In mathematically term,

$V = w\times l\times d$

Where, w = width

h = height

l = length

Put the unit into the formula

$V = m\times m\times m$

$V =m^3$

This is the unit of volume.

We know that,

Square meters is the unit of area.

Liters per cubic gram is the unit of density.

Gram per cubic centimeter is the unit of density in CGS.

Hence, Cubic meters is the unit of volume.

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2 years ago

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Please help me with this question guys.

katen-ka-za [31]

Answer:

The average speed is 22.2 km/h

Explanation:

Average Speed

Given an object travels a total distance d and took a total time t, then the average speed is:

$\displaystyle \bar v=\frac{d}{t}$

The mailman first drives d1=7 km at v1=15 km/h. The time taken to drive is:

$\displaystyle t1=\frac{d1}{v1}=\frac{7}{15}=0.467\ h$

Then he drives d2=7 km at v2=43 km/h taking a time of:

$\displaystyle t2=\frac{d2}{v2}=\frac{7}{43}=0.163\ h$

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$\displaystyle \bar v=\frac{14}{0.63}=22.2\ km/h$

The average speed is 22.2 km/h

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3 years ago

An isotope undergoes radioactive decay by emitting radiation that has a –1 charge. What other characteristic does the radiation

weeeeeb [17]

Answer: The radiation emitted will have negligible mass number.

Explanation:

Radioactive decay is defined as the process in which an unstable nuclei breaks down into stable nuclei via various methods.

An isotope undergoes a radioactive decay to attain stability.

There are three types of decay process, but the process in which the emitted radiation carries a charge of -1 is beta decay.

Beta decay is defined as the decay process in which a neutron gets converted to a proton and an electron. In this decay process, beta particle is emitted. The emitted particle carries a charge of -1 units and has a mass of 0 units. The released beta particle is also known as electron.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

Hence, the radiation emitted will have negligible mass number.

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3 years ago

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A weather balloon is operating at an altitude at which the density of air is 0.90 kg/m^3. At this altitude, the balloon has a vo

Archy [21]

Answer:

54 N

Explanation:

Draw a free body diagram. There are four forces acting on the balloon. Buoyant force pushing the balloon up, gravity pulling the helium down, gravity pulling the balloon skin down, and gravity pulling the load down.

Apply Newton's second law:

∑F = ma

B − Wh − Wb − L = ma

When the load is at a maximum, the acceleration is 0:

B − Wh − Wb − L = 0

B − Wh − Wb = L

B − mh g − Wb = L

The mass of the helium is its density times its volume:

B − ρh Vh g − Wb = L

Buoyant force is defined as B = ρVg, where ρ is the density of the displaced fluid (in this case, air), V is the volume of the displaced fluid, and g is acceleration of gravity. Since the volume of displaced air = the volume of the helium:

ρa V g − ρh V g − Wb = L

(ρa − ρh) V g − Wb = L

Given that ρa = 0.90 kg/m³, ρh = 0.178 kg/m³, V = 20 m³, g = 9.8 m/s², and Wb = 88 N:

(0.9 − 0.178) (20) (9.8) − (88) = L

L = 53.5 N

Rounded to 2 sig-figs, the maximum load that can be supported is 54 N.

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3 years ago

A large room in a house holds 947 kg of dry air at 33.2°C. A woman opens a window briefly and a cool breeze brings in an additio

BartSMP [9]

Answer:

31.96362 °C

Explanation:

$m_1$ = Mass of air in the room = 947 kg

$m_2$ = Mass of air entering the room = 62.4 kg

$T_1$ = Temperature in the room = 33.2°C

$T_2$ = Temperature air entering the room = 13.2°C

T = Equilibrium temperature

c = Specific heat of air = 1006 J/kg °C

In the case of thermal equilibrium we have the relation

$m_1c(T_1-T)=m_2c(T-T_2)\\\Rightarrow T=\frac{m_2T_2+m_1T_1}{m_1+m_2}\\\Rightarrow T=\frac{62.4(13.2+273.15)+947(33.2+273.15)}{947+62.4}\\\Rightarrow T=305.11362\ K=305.11362-273.15=31.96362^{\circ}C$

The temperature of thermal equilibrium is 31.96362 °C

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