3 years ago

Don't you ever feel like thursday is like the number 7?

Physics

1 answer:

Ostrovityanka [42]3 years ago

5 0

Bruh whatttt sjskskskskdk

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Most of the currents identified have a circular shape. This is because as the air and water move between the equator to the pole

Morgarella [4.7K]

I believe it is true . Somebody correct me if I’m wrong!

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2 years ago

English or metric <br> What is 16in to cm

il63 [147K]

40.64 cm is the answer to your question.

6 0

3 years ago

The voltage in a circuit is given by the equation V = IR . In this equation , Vis the voltage, the current, and Ris the resistan

Mumz [18]

Answer:

The choice D.

$R = \frac{v}{I}$

I hope I helped you^_^

8 0

3 years ago

a uniform rod is hung at onen end and is partially submerged in water. If the density of the rod is 5/9 than of wter, find the f

34kurt

Answer:

$\frac{h_{liquid} }{ h_{body} }$ = 5/9

Explanation:

This is an exercise that we can solve using Archimedes' principle which states that the thrust is equal to the weight of the desalted liquid.

B = ρ_liquid g V_liquid

let's write the translational equilibrium condition

B - W = 0

let's use the definition of density

ρ_body = m / V_body

m = ρ_body V_body

W = ρ_body V_body g

we substitute

ρ_liquid g V_liquid = ρ_body g V_body

$\frac{\rho_{body} }{\rho_{liquid} } } = \frac{V_{liquid} }{V_{body} } }$

In the problem they indicate that the ratio of densities is 5/9, we write the volume of the bar

V = A h_bogy

Thus

$\frac{V_{liquid} }{V_{1body} } = \frac{ h_{liquid} }{h_{body} }$

we substitute

5/9 = $\frac{h_{liquid} }{ h_{body} }$

8 0

2 years ago

It is 5.5 km from your home to the physics lab. As part of your physical fitness program, you could run that distance at 10 km/h

stealth61 [152]

Explanation:

Displacement = 5 km

Converting km/h to m/s,

10 km/h * 1000 m/1 km * 1 h/3600 s

= 25/9 m/s

Remember,

700 watt = 700 J/s

Velocity = displacement/time

Time = 5000/(25/9)

= 1800 s

Energy = power * time

= 700 * 1800

= 1,260,000

= 1260 kJ

Converting km/h to m/s,

3 km/h * 1000 m/1 km * 1 h/3600 s

= 5/6 m/s

290 watt = 290 J/s

Velocity = displacement/time

Time = 5000/(5/6)

= 6000 s

Energy = power * time

= 290 * 6000

= 1,740,000

= 1740 kJ

Walking burns more energy; 1,740,000 joules. It burns more because you walk for a greater period of time.

6 0

3 years ago