La velocidad correcta de la luz en el vacío es 300.000 km/s .
La distancia = (velocidad) x (duración de tiempo)
Duración de tiempo = 494 segundos, porque cada minuto = 60 segundos
La distancia = (300.000 km/s) x (494 s)
<em>La distancia = 148.200.000 km</em>
Answer:
![0.11\times 10^{-6}weber](https://tex.z-dn.net/?f=0.11%5Ctimes%2010%5E%7B-6%7Dweber)
Explanation:
We have given number of turns N = 560
Inductance L = 8.9 mH
Current through the coil = 7 mA
Inductance of the coil is given as ![L=\frac{N\Phi }{I}](https://tex.z-dn.net/?f=L%3D%5Cfrac%7BN%5CPhi%20%7D%7BI%7D)
Where N is number of turns I is current and
is flux
So ![\Phi =\frac{LI}{N}=\frac{8.9\times 10^{-3}\times 7\times 10^{-3}}{560}=0.11\times 10^{-6}weber](https://tex.z-dn.net/?f=%5CPhi%20%3D%5Cfrac%7BLI%7D%7BN%7D%3D%5Cfrac%7B8.9%5Ctimes%2010%5E%7B-3%7D%5Ctimes%207%5Ctimes%2010%5E%7B-3%7D%7D%7B560%7D%3D0.11%5Ctimes%2010%5E%7B-6%7Dweber)
Complete Question:
Check the file attached to get the complete question
Answer:
In the film Ice word Revenge, vehicle 2 did not fall of the cliff because,
but in Claire's test, vehicle 2 off the cliff because ![Weight_{vehicle 1} \geq Weight_{vehicle 2}](https://tex.z-dn.net/?f=Weight_%7Bvehicle%201%7D%20%5Cgeq%20Weight_%7Bvehicle%202%7D)
Explanation:
In Claire's test, the weight of vehicle 1 is either equal to or greater than the weight of vehicle 2, so it was sufficient to push it down the cliff. In the film Ice word revenge, the weight of vehicle 1 is less than the weight of vehicle 2, it is not sufficient to make it fall off the cliff ( Note: Looking exactly the same in the movie, as Claire claimed, does not mean they have the same mass). Therefore if Claire wants a collision that will not make the vehicle 2 fall off the cliff, he should collide it with a vehicle of lesser mass/weight.
Answer:
it becomes a gas
Explanation:
the matter expands, turning into steam, a gas.
here as it is given that x component of the vector is positive while y component of the vector is negative so we can say the vector must inclined in Fourth quadrant.
So angle must be more than 270 degree and less than 360 degree
Now in order to find the value we can say that
![tan\theta = \frac{opposite\: side}{adjacent\: side}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7Bopposite%5C%3A%20side%7D%7Badjacent%5C%3A%20side%7D)
![tan\theta = \frac{8.6}{6.1}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7B8.6%7D%7B6.1%7D)
![\theta = tan^{-1}1.41](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%5E%7B-1%7D1.41)
![\theta = 54.65^0](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2054.65%5E0)
so it is inclined at above angle with X axis in fourth quadrant
Now if angle is to be measured counterclockwise then its magnitude will be
![\theta = 360 - 54.65 = 305.3^0](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20360%20-%2054.65%20%3D%20305.3%5E0)
so the correct answer will be 305 degree