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4 years ago

6

A ball is rolled uphill a distance of 12 meters before it slows, stops, and begins to roll back. The ball rolls downhill 20 mete

rs before coming to rest against a tree. What is the magnitude of the ball’s displacement________ m

1 answer:

Sedaia [141]4 years ago

5 0

The ball rolled a distance of
d = 12m + 20m.
But the change of position is
x = + 12m - 20m

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How far from the base of the platform does she land?

seropon [69]

When Janet leaves the platform, she's moving horizontally at 1.92 m/s. We assume that there's no air resistance, and gravity has no effect on horizontal motion. There's no horizontal force acting on Janet to make her move horizontally any faster or slower than 1.92 m/s.

She's in the air for 1.1 second before she hits the water.

Moving horizontally at 1.92 m/s for 1.1 second, she sails out away from the platform

(1.92 m/s) x (1.1 sec) = <em>2.112 meters</em>

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3 years ago

find the distance traveled in km when the average speed is 60 km per hour and the time taken is 3 and 1/2 hours

Anna35 [415]

Answer:

210 km

Explanation:

60 x 3 1/2 = 210

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3 years ago

How to solve 30(a)<br><br> Give solution asap.

expeople1 [14]

Answer:

They will not meet

h-hX=1.2*g*t²

hX=v0*t-(1/2*g*t²)

Explanation:

fall h=1/2*g*t²

elevation time if v0=20 m/s te=v0/g=20 m/s /9.81 m/s²=2.0387s

hmax=v0²/(2*g)=(400 m²/s²)/19.62 m/s²2=20.387 m

free fall

t=2.0387s yields hX=1/2*g*t²=20.387 m

h-hX=200m - 20.387 m=179,613 m.

so, the second body has not enough initianoal speed to reach a meeting point

5 0

3 years ago

The mass of M1 = 12 Daltons and it has a speed of v1 = 200 m/s. The mass of M2 = 4 Daltons. What was the total momentum of the s

svet-max [94.6K]

Answer:

The total momentum is $p__{T }} =(2400 -4 v_2) \ Dalton \cdot m/s$

Explanation:

The diagram illustration this system is shown on the first uploaded image (From physics animation)

From the question we are told that

The mass of the first object is $M_1 = 12 \ Dalton$

The speed of the first mass is $v_1 = 200 \ m/s$

The mass of the second object is $M_2 = 4 \ Dalton$

The speed of the second object is assumed to be $- v_2$

The total momentum of the system is the combined momentum of both object which is mathematically represented as

$p__{T }} = M_1 v_1 + M_2 v_2$

substituting values

$p__{T }} = 12 * 200 + 4 * (-v_2)$

$p__{T }} =(2400 -4 v_2) \ Dalton \cdot m/s$

7 0

3 years ago

A ski tow operates on a slope of angle 15.6 ∘ of length 340 m . The rope moves at a speed of 12.7 km/h and provides power for 53

GREYUIT [131]

Answer:

P = 34034.2 Watt

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As we know that the slope angle is given as

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now the weight of the rider along the slope is given as

$W = mgsin\theta$

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$W = 182 N$

now total weight of all 53 riders along the slope is given as

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now the speed of the rope is given as

$v = 12.7 km/h = 3.53 m/s$

now the power required is given as

$P = F.v$

$P = 9647.5(3.53)$

$P = 34034.2 Watt$

3 0

3 years ago