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melamori03 [73]
4 years ago
7

The international governing body for badminton is the

Physics
2 answers:
vekshin14 years ago
4 0
<span>The Badminton World Federation</span>
Amanda [17]4 years ago
4 0
The Badminton World Federation (BWF<span>)</span>
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A 0.18-kg turntable of radius 0.32 m spins about a vertical axis through its center. A constant rotational acceleration causes t
borishaifa [10]

Answer:

Angular acceleration will be 18.84rad/sec^2

Explanation:

We have given that mass m = 0.18 kg

Radius r = 0.32 m

Initial angular velocity \omega _i=0rev/sec

And final angular velocity \omega _f=24rev/sec

Time is given as t = 8 sec

From equation of motion

We know that \omega _f=\omega _i+\alpha t

24=0+\alpha \times 8

\alpha =3rev/sec^2=3\times 2\times \pi rad/sec^2=18.84rad/sec^2

So angular acceleration will be 18.84rad/sec^2

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4 years ago
When Pluto was classified as a planet it was known as a oddball planet why? Why is it less if an oddball now?
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a strange world that has baffled scientists ever since it was discovered in 1930. It is not the large gas giant that one might expect to find in the outer reaches of the solar system.

Explanation:

Explanation

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3 years ago
Which muscles help you sit up from laying down?​
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3 0
3 years ago
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Una cámara fotográfica analógica (no digital) tiene dos lentes intercambiables. Uno de foco 55mm y el otro de 200 mm. Toma una f
Sergeu [11.5K]

Answer:

f = 55mm,     h ’= -9.89 cm

f = 200 mm,  h ’= 42.5 cm

Explanation:

For this exercise let's start by finding the distance to the image, using the equation of the constructor

         \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distances to the object and image, respectively

lens with f₁ = 55mm = 0.55cm

         \frac{1}{q} = \frac{1}{f} - \frac{1}{p}

         \frac{1}{q_1} = \frac{1}{0.55} - \frac{1}{10}

          \frac{1}{q_1} = 1.718

          q₁ = 0.582 m

lens with f₂ = 200mm = 2m

           \frac{1}{q_2} =   \frac{1}{2} - \frac{1}{10}

            \frac{1}{q_2} = 0.4

            q₂ = 2.5 m

the magnification of a lens is given by

            m = \frac{h'}{h} = -  \frac{q}{p}

             h ’= - \frac{q}{p} \ h

let's calculate for each lens

f = 55mm

             h '= - 0.582 / 10 1.7

             h ’= 0.0989 m

             h ’= -9.89 cm

f = 200 mm

             h '= - 2.5 / 10 1.7

             h ’= -0.425 m

             h ’= 42.5 cm

The negative sign indicates that the image is real and inverted

4 0
3 years ago
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