Answer:
14 m/s
Explanation:
Using the principle of conservation of energy, the potential energy is converted to kinetic energy, assuming any losses.
Kinetic energy is given by ½mv²
Potential energy is given by mgh
Where m is the mass, v is the velocity, g is acceleration due to gravity and h is the height.
Equating kinetic energy to be equal to potential energy then
½mv²=mgh
V
Making v the subject of the formula
v=√(2gh)
Substituting 9.81 m/s² for g and 10 m for h then
v=√(2*9.81*10)=14.0071410359145 m/s
Rounding off, v is approximately 14 m/s
Answer:
(a) 2.03 m/s
(b) 2.15 m/s
Explanation:
(a)
From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum
Momentum, p=mv where m is the mass and v is the velocity
where 
is the common velocity, 
and 
are velocities of the first railroad car and the second railroad car respectively, 
and 
are masses of the first railroad car and the second railroad car respectively
Substituting the given figures then
(b)
Momentum, p=mv where m is the mass and v is the velocity
where and are initial velocities of the ball moving towards west and the other ball moving in opposite direction respectively, and are masses of the first railroad car and the second railroad car respectively
Taking west as positive then the opposite direction will be negative hence
Note that when the 0.455 rebounds, it moves towards East and since we took West as positive that is why we give 15.4 as a negative value.
towards East
Answer:
a) 5.63 atm
Explanation:
We can use combined gas law
<em>The combined gas law</em> combines the three gas laws:
- Boyle's Law, (P₁V₁ =P₂V₂)
- Charles' Law (V₁/T₁ =V₂/T₂)
- Gay-Lussac's Law. (P₁/T₁ =P₂/T₂)
It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.
P₁V₁/T₁ =P₂V₂/T₂
where P = Pressure, T = Absolute temperature, V = Volume occupied
The volume of the system remains constant,
So, P₁/T₁ =P₂/T₂
a) 
Answer:
Explanation:
Height attained by body = 50 cm
= .5 m
Initial velocity = u
v² = u² - 2gh
0 = u² - 2gh
u² = 2 x 9.8 x .5
u = 3.13 m /s
During the initial period , the muscle stretches by around 10 cm during which force by ground reacts on the body and gives acceleration to achieve velocity of 3.13 m/s from zero .
v² = u² + 2as
3.13² = 0 + 2 a x .10
a = 49 m/s²
reaction by ground R
Net force
R-mg = ma
R= m ( g +a )
= mg + ma
=W + (W/g) x a
W ( 1 + a / g )
= W ( 1 + 49 / 9.8 )
= 6W
Answer:
<h3>C. electrial</h3>
Explanation:
<h3>I hope l helped you. </h3><h3>Please follow me. ❤❤❤❤</h3>
