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kipiarov [429]
3 years ago
14

Tiny cell structure that carry out specific functions within the cell

Physics
1 answer:
RSB [31]3 years ago
8 0

Answer:

Organelles

Explanation:

I learned this in science.

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What reasoning is empirical in nature
nikdorinn [45]

Answer:

inductive reasoning

Explanation:

6 0
3 years ago
Read 2 more answers
(BRAINLIEST)<br><br> Question: Name 2 waves that you use in your everyday life.
Archy [21]

-- Radio waves.  (To hear the weather while I'm waking up.)

-- Light waves.  (To see where the dog is so I don't step on him.)

-- Infrared waves. (To make my toast for breakfast.)

-- Microwaves.  (To heat my oatmeal for breakfast.  Also when I go in to my job as a microwave communications engineer.)

8 0
4 years ago
What is the magnitude of the total acceleration of point A after 2 seconds? The bar starts from rest and has a constant angular
monitta

Answer:

a_total = 2 √ (α² + w⁴) ,   a_total = 2,236 m

Explanation:

The total acceleration of a body, if we use the Pythagorean theorem is

          a_total² = a_T²2 + a_{c}²

where

the centripetal acceleration is

  a_{c} = v² / r = w r²

tangential acceleration

   a_T = dv / dt

angular and linear acceleration are related

         a_T = α  r

we substitute in the first equation

       a_total = √ [(α r)² + (w r² )²]

       a_total = 2 √ (α² + w⁴)

Let's find the angular velocity for t = 2 s if we start from rest wo = 0

        w = w₀ + α t

        w = 0 + 1.0 2

        w = 2.0rad / s

       

we substitute

        a_total = r √(1² + 2²) = r √5

        a_total = r 2,236

In order to finish the calculation we need the radius to point A, suppose that this point is at a distance of r = 1 m

         a_total = 2,236 m

7 0
4 years ago
A railroad car of mass 2.00 3 104 kg moving at 3.00 m/s collides and couples with two coupled railroad cars, each of the same ma
FrozenT [24]

Given:

Mass of the rail road car, m = 2 kg

velocity of the three cars coupled system, v' = 1.20 m/s

velocity of first car, v_{a} = 3 m/s

Solution:

a) Momentum of a body of mass 'm' and velocity 'v' is given by:

p = mv

Now for the coupled system according to law of conservation of momentum, total momentum of a system before and after collision remain conserved:

mv_{a} + 2mv_{b} = (m + 2m)v'                        (1)

where,

v_{a} = velocity of the first car

v_{b} = velocity of the 2 coupled cars after collision

Now, from eqn (1)

v' = \frac{v_{a} + 2v_{b}}{3}

v' = \frac{3.00 + 2\times 1.20}}{3}

v' = 1.80 m/s

Therefore, the velocity of the combined car system after collision is 1.80 m/s

7 0
3 years ago
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Waldo gets stopped by the police.
STALIN [3.7K]

Answer:

At least they found him.

Explanation:

3 0
2 years ago
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