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3 years ago

Rewrite 0.000000000333 in scientific notation.

2 answers:

6 0

Hello!! Your answer would be 3.33x10^-10. Since you are trying to find one place holder for the notation, you will move your decimal 10 times to the right for it to be in scientific notation. Always remember that for scientific notation, you must have one whole number in front of a decimal at all times. After you put the decimal after the first whole number, count how many times you have moved your decimal. If you have a lot of zeros in front of your numbers, you will always have a negative exponent, and if you have a negative exponent, then you will have a lot of zeros. If you have a whole number exponent, it will be up in the 100s, 1000s, or 10000s, something like that. It will have a high value with a higher exponent. I hope I helped!! If you have any more questions then do not hesitate to message me and let me know. Have a great day!! :)

charle [14.2K]3 years ago

6 0

3.33 times 10^-10 , if you need an explanation as to why let me know

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3 years ago

You have a 150mL sample of an aqueous solution at 25C. It contains 15.2mg of an unknown nonelectrolyte compound. If the solution

Serga [27]

The molar mass of the compound:

If the solution has an osmotic pressure of 8.44 torr, then the molar mass of the unknown non-electrolyte is 223.14 g.

What is osmosis?

Osmosis is defined as the flow of solvent molecules through semi-permeable membrane.
Osmotic pressure is the pressure applied to stop the flow of solvent molecules.
It is a colligative property that means osmotic pressure depends on the number of solute particles .

Therefore,

π $V=inRT$ ( for electrolytes)

Where, π= Osmotic pressure

i = Van 't Hoff factor

n= moles

R= Gaseous constant = 62.363577 L torr $mol^{-1}K^{-1}$

T= Temperature

V= Volume of solution

Given:

T= 298K

V= 150 mL= 0.150 L

Given mass of unknown electrolyte= 15.2 mg = 15.2 x $10^{-3}$ g

Osmotic pressure= 8.44 torr

Molar mass= ?

For non-electrolytes:

πV = n RT

πV= $\frac{m}{M}$ RT

Calculations:

Putting the given values in the formula:

8.44 x 0.150 =15.2 x $10^{-3}$ / M x 62.36 x 298

1.266 = 282.5/M

M = 282.5/1.266

M = 223.14 g

Therefore,

The molar mass of the unknown non-electrolyte is 223.14g.

Learn more about Osmotic pressure here,

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7 0

2 years ago

Which of the following are examples of chemical changes? Select all that apply.

Natali5045456 [20]

Answer:

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2 years ago

Gallium oxide, Ga.Oy, forms when gallium is combined with oxygen. A 1.25 g of Ga is allowed to react with excess oxygen and 1.68

mrs_skeptik [129]

Answer : The chemical formula of a compound is, $Ga_2O_3$

Solution : Given,

Mass of gallium = 1.25 g

Mass of gallium oxide = 1.68 g

Mass of oxygen = Mass of gallium oxide - Mass of gallium

Mass of oxygen = 1.68 - 1.25 = 0.43 g

Molar mass of Ga = 69.72 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of Ga = $\frac{\text{ given mass of Ga}}{\text{ molar mass of Ga}}= \frac{1.25g}{69.72g/mole}=0.0179moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{0.43g}{16g/mole}=0.027moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ga = $\frac{0.0179}{0.0179}=1$

For O = $\frac{0.027}{0.0179}=1.5$

The ratio of Ga : O = 1 : 1.5

To make in whole number we multiple ratio by 2, we get:

The ratio of Ga : O = 2 : 3

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = $Ga_2O_3$

The empirical formula weight = 2(69.72) + 3(16) = 187.44 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

$n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}$

$n=\frac{187.44}{187.44}=1$

Molecular formula = $(Ga_2O_3)_n=(Ga_2O_3)_1=Ga_2O_3$

Therefore, the chemical of the compound is, $Ga_2O_3$

5 0

3 years ago