When your fixing a car, what is the first thing you want to do?

Build a 3-input XOR gate using a 3x8 decoder and an Or gate.please Quickly i have final

lana [24]

Answer:

Take a 3 to 8 decoder with active low outputs

Assuming you are familiar with the functioning of decoders,

The three inputs of decoder of course are the first, second and the carry bit which you feed to the subtractor.

Next we examine the truth table of the full subtractor i formatted in the picture.

Then write the minterms for the difference output and borrow output from the given truth table picture I have mentioned before!!

Explanation:

hopi it to help you!!

7 0

3 years ago

Your program must output each student’s name in the form: last name followed by a comma, followed by a space, followed by the fi

Reptile [31]

Answer:

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

char getStudentGrade(int testScore);

//Declare constant max students in file 10

const int maxStudents = 10;

struct StudentType

{

string studentFName;

string studentLName;

int testScore;

char grade;

};

void readStudentData(StudentType students[]){

int i = 0;

ifstream infile;

infile.open("inputStudentData.txt");

while (!infile.eof())

{

infile >> students[i].studentFName;

infile >> students[i].studentLName;

infile >> students[i].testScore;

students[i].grade = getStudentGrade(students[i].testScore);

i++;

}

char getStudentGrade(int testScore){

char grade;

if(testScore >= 80) {

grade = 'A';

}

else if(testScore >= 60) {

grade = 'B';

}

else if(testScore >= 50) {

grade = 'C';

}

else if(testScore >= 40) {

grade = 'D';

}

else {

grade = 'F';

}

return grade;

}

int main()

{

StudentType students[10];

readStudentData(students);

for(int i=0;i<maxStudents;i++) {

students[i].grade = getStudentGrade(students[i].testScore);

}

for(int i=0; i<maxStudents; i++){

cout << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

}

ofstream outputFile;

outputFile.open ("outputStudentData.txt");

for(int i=0; i<maxStudents; i++){

outputFile << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

}

outputFile.close();

return 0;

}

3 0

3 years ago

With a very precise volumetric measuring device, the volume of a liquid sample is determined to be 6.321 L (liters). Three stude

zheka24 [161]

Answer:

See explanation

Explanation:

Solution:-

- Three students measure the volume of a liquid sample which is 6.321 L.

- Each student measured the liquid sample 4 times. The data is provided for each measurement taken by each student as follows:

Students

Trial A B C

1 6.35 6.31 6.38

2 6.32 6.31 6.32

3 6.33 6.32 6.36

4 6.36 6.35 6.36

- We will define the two terms stated in the question " precision " and "accuracy"

- Precision refers to how close the values are to the sample mean. The dense cluster of data is termed to be more precise. We will use the knowledge of statistics and determine the sample standard deviation for each student.

- The mean measurement taken by each student would be as follows:

$E ( A ) = \frac{6.35 +6.32+6.33+6.36}{4} \\\\E ( A ) = 6.34\\\\E ( B ) = \frac{6.31 +6.31+6.32+6.35}{4} \\\\E ( B ) = 6.3225\\\\E ( C ) = \frac{6.38 +6.32+6.36+6.36}{4} \\\\E ( C ) = 6.355\\$

- The precision can be quantize in terms of variance or standard deviation of data. Therefore, we will calculate the variance of each data:

$Var ( A ) = \frac{6.35^2+6.32^2+6.33^2+6.36^2}{4} - 6.34^2\\\\Var ( A ) = 0.00025\\\\Var ( B ) = \frac{6.31^2+6.31^2+6.32^2+6.35^2}{4} - 6.3225^2\\\\Var ( B ) = 0.00026875\\\\Var ( C ) = \frac{6.38^2+6.32^2+6.36^2+6.36^2}{4} - 6.355^2\\\\Var ( C ) = 0.000475\\$

- We will rank each student sample data in term sof precision by using the values of variance. The smallest spread or variance corresponds to highest precision. So we have:

Var ( A ) < Var ( B ) < Var ( C )

most precise Least precise

- Accuracy refers to how close the sample mean is to the actual data value. Where the actual volume of the liquid specimen was given to be 6.321 L. We will evaluate the percentage difference of sample values obtained by each student .

$P ( A ) = \frac{6.34-6.321}{6.321}*100= 0.30058\\\\P ( B ) = \frac{6.3225-6.321}{6.321}*100= 0.02373\\\\P ( C ) = \frac{6.355-6.321}{6.321}*100= 0.53788\\$

- Now we will rank the sample means values obtained by each student relative to the actual value of the volume of liquid specimen with the help of percentage difference calculated above. The least percentage difference corresponds to the highest accuracy as follows:

P ( B ) < P ( A ) < P ( C )

most accurate least accurate

7 0

3 years ago

An article that discusses pharaohs and gives examples and explains how they look. Which text structure is that?

fgiga [73]

The correct answer to this open question is the following.

The text structure of an article that discusses pharaohs and gives examples and explains how they look is a description.

The text structure called description allows the reader to fully know the characteristics of the people it is referring to, including some important details. That is why the author of a description text adds words like "such as" and "for example."

When describing something, the write is giving structure to the text and sequence. What comes first., what is followed, and so on.

That is why The text structure of an article that discusses pharaohs and gives examples and explains how they look is a description. It includes cause and effect sentences, and some comparisons in order to contrast an idea.

3 0

3 years ago

Luợng hơi nước có lưu lượng 100kg/s ở áp suất đầu p;= 20bar, nhiệt độ đầu t; =400°C giãn nở đoạn nhiệt trong tuabin đến độ khô X

Valentin [98]

Answer:

Explanation:

.

3 0

3 years ago