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astra-53 [7]
3 years ago
10

Joseph wants to practice architecture. Which compulsory assessment administered by NCARB does he need to complete?

Engineering
1 answer:
Hunter-Best [27]3 years ago
8 0

Answer:

Architect Registration Examination (ARE)

Explanation:

In this scenario, Joseph wants to practice architecture. A compulsory assessment administered by National Council of Architectural Registration Boards (NCARB) which he has to complete is an Architect Registration Examination.

An Architect Registration Examination (ARE) refers to the professional licensure examination to be taken by anyone who intends to practice architecture in the United States of America, Puerto Rico, Guam, Canada, US Virgin Islands.

The main purpose of the Architect Registration Examination is to assess an architect's knowledge, skills, and abilities on architectural best practices, procedures and services. Also, it focuses on areas relating to a building's safety, soundness and health impact on the habitants. Therefore, ARE is a prerequisite for practicing architecture across the United States of America jurisdiction.

Once an architect passes the examination, he or she would be given a license to practice architecture.

<em>Hence, for Joseph to practice architecture he must take the Architect Registration Examination developed and administered by National Council of Architectural Registration Boards (NCARB). </em>

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(a) The lower yield point for an iron that has an average grain diameter of 1 x 10-2 mm is 230 MPa. At a grain diameter of 6 x 1
olya-2409 [2.1K]

Answer:

The answer is "4.35 \times 10^{-3}\  mm and 157.5 MPa".

Explanation:

In point A:

The strength of its products with both the grain dimension is linked to this problem. This formula also for grain diameter of 310 MPA is represented as its low yield point  

y =  yo + \frac{k}{\sqrt{x}}

Here y is MPa is low yield point, x is mm grain size, and k becomes proportionality constant.  

Replacing the equation for each condition:  

y = y_o + \frac{k}{\sqrt{(1 \times 10^{-2})}}\\\\\ \ \ \ \ \ \ 230 = yo + 10k\\\\ y = yo + \frac{k}{\sqrt{(6\times 10^{-3})}}\\\\275 = yo + 12.90k

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To substitute the answer,  

310 = 275 + \frac{(15.5)}{\sqrt{x}}\\\\x = 0.00435 \ mm = 4.35 \times 10^{-3}\  mm

In point b:

The equation is \sigma y = \sigma 0 + k y d^{\frac{1}{2}}

equation is:

75 = \sigma o+4 ky \\\\175 = \sigma o+12 ky\\\\ky = 12.5 MPa (mm)^{\frac{1}{2}} \\\\ \sigma 0 = 25 MPa\\\\d= 8.9 \times 10^{-3}\\\\d^{- \frac{1}{2}} =10.6 mm^{-\frac{1}{2}}\\

by putting the above value in the formula we get the \sigma y value that is= 157.5 MPa

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