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lubasha [3.4K]
3 years ago
12

Identify the compounds that are soluble in both water and hexane. identify the compounds that are soluble in both water and hexa

ne. 1-propanol and 1-pentanol 1-butanol and 1-pentanol ethanol and 1-butanol ethanol and 1-propanol methanol and 1-butanol
Chemistry
2 answers:
MariettaO [177]3 years ago
7 0

\boxed{{\text{Ethanol and 1 - propanol}}} are soluble in both water and hexane.

Further explanation:

The property of any substance (solute) that makes it able to dissolve in other solvents or substances is known as solubility. It depends on the physical and chemical properties of both solute and solvent. The solute is the component that is present in a smaller amount while the solvent is present in a larger amount. The solubility is generally determined by the principle of “like dissolves like”.

Hexane is a non-polar hydrocarbon consisting of six carbon atoms linked to each other in a straight chain. Water is a polar solvent due to the presence of a highly electronegative oxygen atom in it.

Alcohols have the general formula of ROH, where R represents the carbon chains or rings attached to the hydroxyl functional group. So alcohols have both polar as well as non-polar parts in them.

Smaller alcohols such as methanol, ethanol, and propanol are soluble in water due to their hydroxyl groups. These can form hydrogen bonds with water and becomes soluble in it. But larger alcohols have a large, non-polar part which is hydrophobic in nature. So larger alcohols like pentanol, hexanol, heptanol and octanol become insoluble in water. Due to the presence of large non-polar parts in higher members of alcohol, these are also soluble in hexane.

1-propanol is alcohol consisting of three carbon atoms while 1-pentanol has five carbon atoms. So 1-propanol is soluble in water but 1-pentanol is soluble in hexane only.

1-butanol is an alcohol having four carbon atoms whereas 1-pentanol has five carbon atoms. So 1-butanol is slightly soluble in water but 1-pentanol is soluble in hexane only.

Ethanol is the alcohol of two carbon atoms and 1-butanol has four carbon atoms. Ethanol is soluble in water but 1-butanol is slightly soluble in water.

Ethanol is the alcohol of two carbon atoms and 1-propanol has three carbon atoms. Both also contain a non-polar hydrophobic end in them so these are soluble in both water and hexane.

Methanol is the alcohol of one carbon atom while 1-butanol has four carbon atoms in it. Methanol is highly soluble in water but 1-butanol is only slightly soluble in water.

Learn more:

  1. Identification of ionic bonding: brainly.com/question/1603987
  2. What type of bond exists between phosphorus and chlorine? brainly.com/question/81715

Answer details:

Grade: High School

Chapter: Solubility

Subject: Chemistry

Keywords: polar, non-polar, water, hexane, ethanol, 1-propanol, methanol, alcohols, 1-butanol, 1-pentanol, soluble, insoluble, like dissolves like.

Reika [66]3 years ago
4 0
<span>The correct answer would be the fourth option. The compounds ethanol and 1-propanol are soluble to both water and hexane. Ethanol and 1-propanol are completely soluble in water as they both contain a polar end due to the hydrogen bonding present in the -OH functional group. Both are soluble in hexane since both contains a non polar end, the aliphatic hydrocarbon chain. Solubility of alcohols varies increasingly as the hydrocarbon chain increases since it makes them more non polar. However, for branched molecules, non polar properties would decrease. So, the best option from the list of choices would be ethanol and 1-propanol.</span>
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Camphor, a white solid with a pleasant odor, is extracted from the roots, branches, and trunk of the camphor tree. Assume you di
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<u>Answer:</u> The molarity of solution is 0.799 M , molality of solution is 1.02 m, mole fraction of camphor is 0.045 and mass percent of camphor in solution is 13.43 %

<u>Explanation:</u>

  • <u>Calculating the molarity of solution:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of camphor = 70.0 g

Molar mass of camphor = 152.2 g/mol

Volume of solution = 575 mL

Putting values in above equation, we get:

\text{Molarity of camphor}=\frac{70\times 1000}{152.2\times 575}\\\\\text{Molarity of camphor}=0.799M

  • <u>Calculating the molarity of solution:</u>

To calculate the mass of ethanol, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of ethanol = 0.785 g/mL

Volume of ethanol = 575 mL

Putting values in above equation, we get:

0.785g/mL=\frac{\text{Mass of ethanol}}{575mL}\\\\\text{Mass of ethanol}=(0.785g/mL\times 575mL)=451.38g

To calculate the molality of solution, we use the equation:

\text{Molality of solution}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

m_{solute} = Given mass of solute (camphor) = 70 g

M_{solute} = Molar mass of solute (camphor) = 152.2  g/mol

W_{solvent} = Mass of solvent (ethanol) = 451.38 g

Putting values in above equation, we get:

\text{Molality of camphor}=\frac{70\times 1000}{152.2\times 451.38}\\\\\text{Molality of camphor}=1.02m

  • <u>Calculating the mole fraction of camphor:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

<u>For camphor:</u>

Given mass of camphor = 70 g

Molar mass of camphor = 152.2 g/mol

Putting values in equation 1, we get:

\text{Moles of camphor}=\frac{70g}{152.2g/mol}=0.459mol

<u>For ethanol:</u>

Given mass of ethanol = 451.38 g

Molar mass of ethanol = 46 g/mol

Putting values in equation 1, we get:

\text{Moles of ethanol}=\frac{451.38g}{46g/mol}=9.813mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

Moles of camphor = 0.459 moles

Total moles = [0.459 + 9.813] = 10.272 moles

Putting values in above equation, we get:

\chi_{(camphor)}=\frac{0.459}{10.272}=0.045\

  • <u>Calculating the mass percent of camphor:</u>

To calculate the mass percentage of camphor in solution, we use the equation:

\text{Mass percent of camphor}=\frac{\text{Mass of camphor}}{\text{Mass of solution}}\times 100

Mass of camphor = 70 g

Mass of solution = [70 + 451.38] = 521.38 g

Putting values in above equation, we get:

\text{Mass percent of camphor}=\frac{70g}{521.38g}\times 100=13.43\%

Hence, the molarity of solution is 0.799 M , molality of solution is 1.02 m, mole fraction of camphor is 0.045 and mass percent of camphor in solution is 13.43 %

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Explanation:

Vinegar is a sour liquid made up of acetic acid compounds. Oil is a complex non-polar chemical compound with a high amount of hydrogen and carbon in its structure.

  • Vinegar is a polar acid, although a weak one.
  • Generally, for a substance to mix with another one, they must be similar.
  • Solubility of compounds controls miscibility.
  • When two substances are miscible, they can be said to be soluble in one another.
  • In solubility, like substances dissolves like substances.
  • This implies that polar compounds will only dissolve polar compounds.
  • Non-polar compounds will only dissolve in non-polar solvents.
  • Since vinegar is polar and oil is non-polar, they will not dissolve one another.

Learn more:

Polarity brainly.com/question/2615067

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An ion has 14 neutrons, 10 electrons, and a mass number of 27 what element
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The ion is Al³⁺

mass number - number of neutrons= atomic number

27 - 14 = 13

Aluminum has an atomic number of 13, thus we know this is the metal in question. Also, because the aluminum has only 10 electrons, (3 less than a neutral atom of aluminum would have), its charge must be 3+

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Why neon is special from other chemical elements​
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Noble gases react very unwillingly, because the outermost shell of electrons orbiting the nucleus is full, giving these gases no incentive to swap electrons with other elements. As a result, there are very few compounds made with noble gases. Like its noble gas comrades, neon is odorless and colorless.
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What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid?.
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Answer:

What will determine the number of moles of hydronium in an aqueous solution of a strong monoprotic acid? The amount of acid that was added.

Explanation:

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