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andrey2020 [161]
4 years ago
15

Which statement best describes the properties of covalent compounds?

Chemistry
1 answer:
AnnyKZ [126]4 years ago
4 0
Covalent network. <span>A solid that is extremely hard, that has a very high melting point, and that will not conduct electricity either as a solid or when molten is held together by a continuous three-dimensional network of covalent bonds. Examples include diamond, quartz (SiO </span><span>2 </span>), and silicon carbide (SiC). The electrons are constrained in pairs to a region on a line between the centers of pairs of atoms.<span>


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A sample of hydrogen gas occupies 50.4 L at STP. This sample contains how many moles of hydrogen atoms
erik [133]

Answer: 4.5

Explanation:

8 0
3 years ago
The largest atom from among the following is A. Li. B. Na. C. Rb. D. Fr.
erastova [34]
D since Francium has an atomic number (mass) of 87
8 0
3 years ago
Read 2 more answers
Which elements are most metallic? Li, Be, B, C
charle [14.2K]
Firstly, carbon isn't a metal.

Boron is a metalloid.

Beryllium is the least metallic alkaline earth metal, and lithium is the least metallic alkaline metal.

Both are metallic, and have metallic appearances and conduct electricity, but beryllium is more brittle than lithium.

So, I'd say Li and Be are equal.
4 0
4 years ago
Gallium (Ga) consists of two naturally occurring isotopes with masses of 68.926 and 70.925 amu. (a) How many protons and neutron
pav-90 [236]

Answer:

neutrons_{Ga-69}=38\\\\neutrons_{Ga-71}=40

Explanation:

Hello!

In this case, since isotopes of the same element have the same number of protons and electrons but different atomic mass, we can compute the number of neutrons by subtracting the number of protons to the atomic mass of the isotope; thus, for Ga-69 and Ga-71 (rounded up to whole numbers), we obtain:

neutrons_{Ga-69}=69-31=38\\\\neutrons_{Ga-71}=71-31=40

Best regards!

8 0
3 years ago
1. Determine the final volume of a 1.5 M HCl solution prepared from 20.0 mL
nadezda [96]

Explanation:

Because molarity is classified as moles of solute per liter of water, dilution of the water may result in a reduction of its concentration.

Therefore, because the amount of moles of solute has to be constant for dilution, you will use the molarity and volume of that same target solution to calculate how many moles of solute will be present in the sample of the stock solution that you dilute.

c  =   \frac{n}{v}

⇒  n = c ⋅  V

n_{HCL} =  0.250 M  ⋅  6.00 L  = 1.5 moles HCl

Now all you have to do is figure out what volume of   6.0 M  stock solution will contain  1.5  moles of hydrochloric acid

c = \frac{n}{v}

V = \frac{n}{c}

V_{Stock} = \frac{1.5 moles}{6.0 \frac{moles}{L} }   = 0.25 L

Expressed in milliliters, the answer will be

V_{Stock} = 250ML →  rounded to two sig figs

7 0
3 years ago
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