Yes, it's true.
But 2nd Newton Law always come to play when the horse is to move forward because obviously the forces interact antagonistically and mass has to be accounted for.
That's what I think. Hope it's right, all the best.
Answer:
Depending on where people are located in the world (Northern hemisphere, Southern hemisphere, etc) depends on the difference in direction (North, South, east, West) which is most likely why it'd look different.
Explanation:
I dunno if this is along the lines of an answer you're looking for, but hope this helps :)
Answer:
mass
Explanation:
This energy of motion is what we call kinetic energy. ... In fact, kinetic energy is directly proportional to mass: if you double the mass, then you double the kinetic energy. Second, the faster something is moving, the greater the force it is capable of exerting and the greater energy it possesses.
pls make as brainlieast
Explanation:
It is given that,
Magnitude of charge, ![q=15\ \mu C=15\times 10^{-6}\ C](https://tex.z-dn.net/?f=q%3D15%5C%20%5Cmu%20C%3D15%5Ctimes%2010%5E%7B-6%7D%5C%20C)
It moves in northeast direction with a speed of 5 m/s, 25 degrees East of a magnetic field.
Magnetic field, ![B=0.08\ j](https://tex.z-dn.net/?f=B%3D0.08%5C%20j)
Velocity, ![v=(5\ cos25)i+(5\ sin25)j](https://tex.z-dn.net/?f=v%3D%285%5C%20cos25%29i%2B%285%5C%20sin25%29j)
![v=[(4.53)i+(2.11)j]\ m/s](https://tex.z-dn.net/?f=v%3D%5B%284.53%29i%2B%282.11%29j%5D%5C%20m%2Fs)
We need to find the magnitude of force on the charge. Magnetic force is given by :
![F=q(v\times B)](https://tex.z-dn.net/?f=F%3Dq%28v%5Ctimes%20B%29)
![F=15\times 10^{-6}[(4.53i+2.11j)\times 0.08\ j]](https://tex.z-dn.net/?f=F%3D15%5Ctimes%2010%5E%7B-6%7D%5B%284.53i%2B2.11j%29%5Ctimes%200.08%5C%20j%5D)
<em>Since</em>, ![i\times j=k\ and\ j\times j=0](https://tex.z-dn.net/?f=i%5Ctimes%20j%3Dk%5C%20and%5C%20j%5Ctimes%20j%3D0)
![F=15\times 10^{-6}[(4.53i)\times (0.08)\ j]](https://tex.z-dn.net/?f=F%3D15%5Ctimes%2010%5E%7B-6%7D%5B%284.53i%29%5Ctimes%20%280.08%29%5C%20j%5D)
![F=0.00000543\ kN](https://tex.z-dn.net/?f=F%3D0.00000543%5C%20kN)
![F=5.43\times 10^{-6}\ kN](https://tex.z-dn.net/?f=F%3D5.43%5Ctimes%2010%5E%7B-6%7D%5C%20kN)
So, the force acting on the charge is
and is moving in positive z axis. Hence, this is the required solution.