Bacteria( cholera)
Virus( AIDS)
Fungi(athlete's foot)
Protist( malaria)
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Answer:
The mass of the mud is 3040000 kg.
Explanation:
Given that,
length = 2.5 km
Width = 0.80 km
Height = 2.0 m
Length of valley = 0.40 km
Width of valley = 0.40 km
Density = 1900 Kg/m³
Area = 4.0 m²
We need to calculate the mass of the mud
Using formula of density


Where, V = volume of mud
= density of mud
Put the value into the formula


Hence, The mass of the mud is 3040000 kg.
Answer:
The final velocity of the thrower is
and the final velocity of the catcher is
.
Explanation:
Given:
The mass of the thrower,
.
The mass of the catcher,
.
The mass of the ball,
.
Initial velocity of the thrower, 
Final velocity of the ball, 
Initial velocity of the catcher, 
Consider that the final velocity of the thrower is
. From the conservation of momentum,

Consider that the final velocity of the catcher is
. From the conservation of momentum,

Thus, the final velocity of thrower is
and that for the catcher is
.
Answer:
0.84 m
Explanation:
Given in the y direction:
Δy = 0.60 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
0.60 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 0.35 s
Given in the x direction:
v₀ = 2.4 m/s
a = 0 m/s²
t = 0.35 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (2.4 m/s) (0.35 s) + ½ (0 m/s²) (0.35 s)²
Δx = 0.84 m
Answer:
C 2000v its obviously ans because if o is 1000 2 vo is 2000v