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LekaFEV [45]
3 years ago
5

Match these items.

Chemistry
1 answer:
notka56 [123]3 years ago
6 0
Litmus is an indicator
Charged particles are ions
Acids contain H+ ions
Bases contain OH - ions
Hydronium ions are H3O+

Now, I have to take issue with the last one
A base of pH 14 is not a strong base, it would be a highly concentrated base. A strong base is a base that completely deionizes in water.

But technically, for the purpose of your answer strong base = pH 14
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Converting the following mm Hg (torr) to standard
11Alexandr11 [23.1K]

Explanation:

Given:

20.5 torr

78.6 torr

225 torr

Change into atm

Computation:

We know that;

1 torr = 0.00131579 atm

So,

1. 20.5 torr

= 20.5 x 0.00131579 atm

= 0.02697

= 0.027 atm (Approx)

2. 78.6 torr

= 78.6 x 0.00131579 atm

= 0.103090

= 0.103 atm (Approx)

3. 225 torr

= 225 x 0.00131579 atm

= 0.2960

= 0.296 atm (Approx)

5 0
3 years ago
True or false: the most easily ionizable elements are the most electronegative.
ehidna [41]
<span>False, This is because when you can easily ionize and atom or the chances of it being ionizable are quite high, it means that that particular atom have very low ionization potential that is the reason why it was easily ionizable An atom with a high ionization power and a firmly negative electron fondness will both pull in electrons from different particles and oppose having its electrons taken away; it will be an exceedingly electronegative molecule.</span>
3 0
3 years ago
How does increasing pressure affect the rate of reaction between gases?
Elina [12.6K]

Answer:

B, increases rate of collisions

Explanation:

7 0
2 years ago
Giving brainiest to whoever answers correctly.
Digiron [165]

Answer:250

Explanation:

5 0
3 years ago
The absorbance (????)(A) of a solution is defined as ????=log10(????0????) A=log10⁡(I0I) where ????0I0 is the incident‑light int
bulgar [2K]

Answer:

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

Explanation:

Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times c\times l

where,

A = absorbance of solution

c = concentration of solution

\epsilon = Molar absorption coefficient

l = path length

I_o = incident light

I = transmitted light

Given :

l = 1 cm, c = 1 mg/mL ,\epsilon = 15,000 M^{-1}cm^{-1}

Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol

(1 Da = 1 g/mol)

c = 1 mg /mL = {1mg /mL}{\text{Molar mass of myoglobin}}

c = \frac{1 mg/mL}{ 17800 g/mol} = 5.6179\times 10^{-5} mol/L

1 mg = 0.001 g, 1 mL = 0.001 L

A= 15,000 M^{-1}cm^{-1}\times 5.6179\times 10^{-5} mol/L\times 1 cm

A=0.8426 \approx 0.84

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

5 0
3 years ago
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