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3 years ago

Oil tends to float on water because the density of oil is _____ the density of water.

Physics

1 answer:

Rama09 [41]3 years ago

7 0

Oil is less dense than water so it tends to float on the top of the water. Hope this Helps!

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t requires1200 kg of coal to produce the energy needed to make 1.0 kg of aluminum metal. If a single soda can requires approxima

Lesechka [4]

Answer:

The mass of coal is 108 kg.

Explanation:

Given that,

Energy of coal = 1200 kg

Mass of aluminum = 1.0 kg

Energy required for single soda can = 15 g of Al

Energy required for 6 pack of cans = $6\times15=90\ g\ of\ Al$

We need to calculate the mass of coal

Using formula of mass

$\text{mass of coal}=\dfrac{\text{Energy of coal}\times\text{Energy required for 6 pack of cans}}{\text{Mass of aluminum}}$

Put the value into the formula

$m=\dfrac{1200\times90\times10^{-3}}{1.0}$

Put the value into the formula

$m=108\ Kg$

Hence, The mass of coal is 108 kg.

6 0

3 years ago

According to Ohm’s law, which combination of units is the same as the unit for resistance? volt ÷ ampere ampere × volt volt + am

Maksim231197 [3]

Answer:

volt ÷ ampere

Explanation:

The mathematical form of Ohms law is given by :

V = IR

Where V is voltage

I is current

R is resistance

$R=\dfrac{V}{I}$

The unit of voltage is volt and that of current is ampere

Unit of resistance :

$R=\dfrac{\text{volt}}{\text{ampere}}$

So, volt ÷ ampere is the same as the unit of resistance. Hence, the correct option is (a).

6 0

3 years ago

Read 2 more answers

A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provid

Sergeeva-Olga [200]

Answer:

$8.37*10^5$ rpm

Explanation:

Given that rotational kinetic energy = $4.66*10^9J$

Mass of the fly wheel (m) = 19.7 kg

Radius of the fly wheel (r) = 0.351 m

Moment of inertia (I) = $\frac{1}{2} mr ^2$

Rotational K.E is illustrated as $(K.E)_{rt} = \frac{1}{2} I \omega^2$

$\omega = \sqrt{\frac{2(K.E)_{rt}}{I} }$

$\omega = \sqrt{\frac{2(KE)_{rt}}{1/2 mr^2} }$

$\omega = \sqrt{\frac{4(K.E)_{rt}}{mr^2} }$

$\omega = \sqrt{\frac{4*4.66*10^9J}{19.7kg*(0.351)^2} }$

$\omega = 87636.04$

$\omega = 8.76*10^4 rad/s$

Since 1 rpm = $\frac{2 \pi}{60} rad/s$

$\omega = 8.76*10^4(\frac{60}{2 \pi})$

$\omega = 836518.38$

$\omega = 8.37 *10^5 rpm$

3 0

3 years ago

What is the total number of moles of products involved in the following reaction?

DENIUS [597]

Answer:

Explanation:

You must first make sure the equation is balanced. This one is. Then, you simply add up the coefficients of each compound on the products side of the equation. When the coefficient is not specified, you can assume it is 1 mole. So, in this equation, there is 1 mole of CaCl₂, 1 mole of CO₂, and 1 mole of H₂O = 3 moles.

The reactant side of the equation also has three moles:

1 mole of CaCO₃ and 2 moles of HCl.

5 0

3 years ago

What happens when you add heat to an object and when you cool an object

Katena32 [7]

When you heat up an object three things could possibly happen:

i) Increase in temperature of the object. Imagine heating up water, the temperature increases.

ii) Linear Expansion: The object could increase in length. For example if you heat up a steel rod, the length would increase as a result of linear expansion.

iii) Change of State: The object could change from solid state to liquid state or from liquid state to gaseous state, as the case may be. For example heating ice block to liquid water.

7 0

3 years ago