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masha68 [24]
3 years ago
13

A cat has a mass of 3 kg and runs at a speed of 6 m/s. How much kinetic

Physics
2 answers:
kupik [55]3 years ago
7 0

Answer:

kinetic \: energy =  \frac{1}{2}  \times m {v}^{2}

1/2 × 3 × 6² = 54J

Maslowich3 years ago
3 0

Answer:

54 Joules

Explanation:

recall that kinetic energy is governed by the equation:

K.E = (1/2) mv²

where,

m = mass = given as 3 kg

v = velocity = given as 6 m/s

Substituting these known values into the above equation,

K.E = (1/2) mv²

K.E = (1/2) (3)(6)²

K.E = 54 Joules

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Can we use a clinical thermometer to measure the temperature of a candle flame​
miv72 [106K]

In theory, yes. The 2 problems are the materials used for clinical thermometers, & the temperature capacity of the clinical thermometer. If anything, change the material & extend the measurement threshold. At that point, it wouldn´t be used for clinical garbage anymore.

3 0
3 years ago
car was moving in a straight road of length 320 km it covered 240 km with an average velocity 75 km/hr then it ran out of fuel a
Stella [2.4K]

The average velocity of the car for the whole journey is 69.57 km/h.

The given parameters:

  • <em>Length of the road, L = 320 km</em>
  • <em>Distance covered = 240 km at 75 km/h</em>
  • <em>time spent refueling, t₂ = 0.6 hr</em>
  • <em>Final velocity, = 100 km/hr</em>

The time spent by the before refueling is calculated as follows;

t = \frac{d}{v} \\\\t_1 = \frac{240}{75} \\\\t_1 = 3.2 \ hours

The time spent by the car for the remaining journey;

t_3 = \frac{320 - 240}{100} \\\\t_3 = 0.8 \ hr

The total time of the journey is calculated as follows;

t = t_1 + t_2 + t_3\\\\t = 3.2 \ hr \ + \ 0.6 \ hr \ + \ 0.8 \ hr\\\\t = 4.6 \ hours

The average velocity of the car for the whole journey is calculated as follows;

v = \frac{total \ distance }{total \ time} \\\\v = \frac{320}{4.6} \\\\v = 69.57 \ km/h

Learn more about average velocity here: brainly.com/question/6504879

6 0
2 years ago
A boat has a propulsion system that consists of a pump that sucks water at the bow and presses it on the stern. All tubes are 5
Phoenix [80]

Answer:

The propulsion force at the moment of departure, is 49 N  

Explanation:

Given;

diameter of tubes = 5 cm = 0.05 m

volumetric flow rate, V = 50 L/s = 0.005 m³/s

density of water, ρ = 1000 Kg /m³

hydraulic / propulsion force, F = ρVg

where;

ρ is the density of the fluid (water)

V is the volumetric flow rate of water

g is acceleration due to gravity

propulsion force, F = ρVg

propulsion force, F = 1000 x 0.005 x 9.8

propulsion force, F = 49 N      

Therefore, the propulsion force at the moment of departure, is 49 N  

7 0
3 years ago
Need help I'll give you 30 points please.
Ksivusya [100]

Cathode Ray Tube i think?

7 0
3 years ago
Which characteristics of rocks are used in classification? Check all that apply.
Elanso [62]

Answer:

i think it is texture and composition

3 0
3 years ago
Read 2 more answers
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