Answer:
The answer is 3.33m
Explanation:
The acceleration "a" is constant.
Acceleration is the variation of velocity over time,
.
solving the last equation
,
where 
because the airplane starts from rest.
Once again, velocity is the variation of distance over time.
then
where 
if we consider the end of the runway as the initial point (this step is for simplicity but you can let it expressed, it's going to cancel anyway).
If 
at 
, then
and the final expression for the distance is
.
If t = 2s, x = 4.44 m. Which means thad the additional distance is
I think it would be clean and store.
Answer:
Ball will not hit bell.
Explanation:
The height of the ball is modeled by the equation h(t)= -16t²+39t
We need to find if the bell is 25 ft above the ground, will it be hit by the ball.
So we need to find maximum height of the ball.
For maximum height we have
Substituting in h(t) = -16t²+39t
Maximum height reached = h(1.22) = -16 x 1.22²+39 x 1.22 = 23.77 ft
So maximum height reached is less than height of bell.
Ball will not hit bell.
Answer:
1000s
Explanation:
because as 2km means 2000m then if the distance is divided my speed the answe comes 1000s
