All categories

2 years ago

When frequency is increased what happens to the amplitude?

1 answer:

6 0

Answer: For sound, a higher frequency corresponds to a higher pitch while a lower frequency corresponds to a lower pitch. Amplitude corresponds to the loudness of the sound. Since sound at all frequencies has the same speed in air, a change in frequency means a change in wavelength.

You might be interested in

At its peak, a tornado is 53.0 m in diameter and carries 465-km/h winds. What is its angular velocity in revolutions per second?

expeople1 [14]

Answer:

0.7757 rev/s

Explanation:

d = Diameter of the tornado = 53 m

r = Radius of the tornado = 53/2 = 26.5 m

v = Velocity of wind = 465 km/h

Converting velocity to m/s

$465=465\times \frac{1000}{3600}=\frac{775}{6}$

Angular velocity

$\omega=\frac{v}{r}\\\Rightarrow \omega=\frac{\frac{775}{6}}{26.5}\\\Rightarrow \omega=4.87\ rad/s$

$\omega=4.87\frac{1}{2\pi}=0.7757\ rev/s$

∴ Angular velocity is 0.7757 rev/s

8 0

3 years ago

The two cars collide at right angles in the intersection of two icy roads. Car A has a mass of 1965 kg and car B has a mass of 1

Sunny_sXe [5.5K]

Answer:

U2 = 47.38m/s = initial velocity of B before impact

Explanation:

An example of the diagram is shown in the attached file because of missing angle of direction in the question

Mass A, B are mass of cars

A = 1965

B =1245

U1 = initial velocity of A = 52km/hr

U2 = initial velocity of B

V = common final velocity of two cars

BU2 = (A + B)*V sin ¤ ...eq1 y plane

AU1 = (A + B) *V cos ¤ ....equ 2plane

From equ 2

V = AU1/(A + B)*cos ¤

Substitute V into equation 1

We have

U2 = (AU1/B)tan ¤ where ¤ = angle of direction which is taken to be 30°

Substitute all parameters to get

U2 = (1965/1245)*52 * tan 30°

U2 = 47.38m/s

8 0

3 years ago

Boyle’s law states that the volume of a gas is inversely proportional to its pressure if the

Romashka [77]

I believe the answer is A, temperature and number of particles are constant. Correct me if i'm wrong :)

4 0

3 years ago

Read 2 more answers

What force is required to accelerate to 10 kg object to 5.9 m/s/s?

g100num [7]

Force required to accelerate 10 kg object to 5.9 m/s/s ?

Mass = 10 kg

Acceleration = 5.9 m/s^2

Force = Mass * Acceleration

Force = 10 kg * 5.9 m/s^2

Force = 59 kg m /s^2 = 59 N

3 0

3 years ago

I WILL MARK YOU THE BRAINLIEST NO LINKS<br>What goes were put them in the correct place

PIT_PIT [208]

Answer:

Fluid fricton goes to Static friction and sliding friction goes to rolling friction

Explanation:

6 0

2 years ago

Read 2 more answers

When frequency is increased what happens to the amplitude￼?

When frequency is increased what happens to the amplitude?