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3 years ago

How is our planets giant,thermohaline system of warm and cold water like a massive convection current

1 answer:

4 0

<span>The planets thermohaline system of warm and cold water is like a massive convection current in the way that it moves water around and seeks to circulate from hot to cold.</span>

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How does the law of conservation of mass apply to this reaction:Al+3HCl-->H2+AlCl3

Veronika [31]

This reaction is unbalanced. If you balance it, it would be:

2Al + 6HCl --> 3H2 + 2AlCl3

That way there are two aluminums on each side, six hydrogens on each side, and six chlorines on each side.

8 0

3 years ago

Football is kicked at 23.4 m/s at a 38.5 angle. How far away does it land?

natulia [17]

Answer: go0gle will know the answer

Explanation: hey I’m not giving fault answers so yea

5 0

3 years ago

Read 2 more answers

Please please help. I don’t understand this.

Kazeer [188]

Which questions do you need help? I could help you

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4 years ago

You are given two rectangular blocks of shiny metal, Block A and Block B, and are asked to determine which one will float in a b

vladimir2022 [97]

Answer:

Explanation:

Volume of block A = 10 x 6 x 1 = 60 cm³

Mass of block A = 630 g

density of mass A = mass / density

= 630 / 60 = 10.5g / cm³

Volume of block B = 5 x 5 x 3 = 75 cm³

Mass of block A = 604 g

density of mass A = mass / density

= 604 / 75 = 8.05 g / cm³

Since density of both A and B are less than that of mercury , both will float in mercury.

7 0

4 years ago

It has been claimed that an insect called the froghopper (Philaenus spumarius) is the best jumper in the animal kingdom. This in

Vladimir [108]

Answer:

v=4m/s

Explanation:

The formulas for accelerated motion are:

$v=v_0+at\\x=x_0+v_0t+\frac{at^2}{2}$

We can derive the formula $v^2=v_0^2+2ad$ from them.

We have:

$v-v_0=at\\t=\frac{v-v_0}{a}$

And substitute:

$x=x_0+v_0(\frac{v-v_0}{a})+\frac{a}{2}(\frac{v-v_0}{a})^2\\x-x_0=\frac{v_0(v-v_0)}{a}+\frac{(v-v_0)^2}{2a}\\2a(x-x_0)=2v_0(v-v_0)+(v-v_0)^2=2v_0v-2v_0^2+v^2+v_0^2-2vv_0=v^2-v_0^2$

Where in the first step of the last row we just multiplied everything by 2a. Since $x-x_0$ is the displacement d, we have proved that $v^2=v_0^2+2ad$

We use then our values to calculate the final velocity when starting from rest, traveling a distance 0.002m with acceleration $4000 m/s^2$ :

$v=\sqrt{v_0^2+2ad}=\sqrt{2(4000m/s^2)(0.002m)}=4m/s$

7 0

3 years ago