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3 years ago

Which statement is correct about an element’s identifying spectrum?

1 answer:

4 0

Atomic line spectra are a series of colored lines that are revealed when the atom is brought to a relaxed state from an excited state.

The colored lines occur due to the fact that electrons give off energy in the form of photons when moving from higher to lower energy level. These photons are in the visible light range and are seen as colors. The line spectra are unique to the element because each element has its own electronic configuration, since it has its own number of electrons.

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Draw a structure for an alcohol that exhibits a molecular ion at M+ = 74 and that produces fragments at m/z = 59, m/z = 56 and m

pychu [463]

Answer:

Please refer to the attachment below for answer and explanation.

Explanation:

Please refer to the attachment below for answer and explanation.

6 0

3 years ago

What does 2n² ?denote explain it with the help of two example<br>

Lana71 [14]

Answer:

2n² means 2 × n × n . the power on the n represent the no. of time it is multiplied.

for ex 3x² = 3 × x × x

4x⁴ = 4 × X× X × X× X

8 0

3 years ago

A 0.580 g sample of a compound containing only carbon and hydrogen contains 0.480 g of carbon and 0.100 g of hydrogen. At STP, 3

Sati [7]

Answer:

Molecular formula for the gas is: C₄H₁₀

Explanation:

Let's propose the Ideal Gases Law to determine the moles of gas, that contains 0.087 g

At STP → 1 atm and 273.15K

1 atm . 0.0336 L = n . 0.082 . 273.15 K

n = (1 atm . 0.0336 L) / (0.082 . 273.15 K)

n = 1.500 × 10⁻³ moles

Molar mass of gas = 0.087 g / 1.500 × 10⁻³ moles = 58 g/m

Now we propose rules of three:

If 0.580 g of gas has ____ 0.480 g of C _____ 0.100 g of C

58 g of gas (1mol) would have:

(58 g . 0.480) / 0.580 = 48 g of C

(58 g . 0.100) / 0.580 = 10 g of H

48 g of C / 12 g/mol = 4 mol

10 g of H / 1g/mol = 10 moles

7 0

3 years ago

1.State the relationship between the following properties:

Diano4ka-milaya [45]

Answer:

bytbyufvguv vvg uggy yvgu vgu gyu7yng8ugng88yn

7 0

3 years ago

what was the initial pressure of 14.8 mL of gas at 75.5 C , when it occupied a volume of 16.5 mL at 70.2 C and 101.3 kPa?

OLEGan [10]

Answer:

1038.96 kPa

Explanation:

We’ll use the ideal gas law; P1V1/T1 = P2V2/T2

P1*14.8/75.5 = 101.3*16.5/70.2

P1 = (101.3 * 16.5 * 75.5) / (70.2 *14.8)

P1 = 1038.96

3 0

3 years ago