5F2 + 2NH3 --> N2F4 + 6HF
<span>60.1g NH3 / 17g/mole = 3.54moles NH3 </span>
<span>3.54moles NH3 x (5 F2 / 2NH3) x 38g/mole = 335.85g required </span>
<span>5.25g HF / 20g/mole = 0.262moles HF </span>
<span>0.262moles HF x (2NH3 / 6HF) x 17g/mole = 1.49g required </span>
<span>209g / 38g/mole = 5.5moles F2 </span>
<span>5.5moles F2 (1 N2F4 / 5F2) x 66g/mole = 72.6g produced </span>
<span>Li3N + 3H2O --> NH3 + 3LiOH </span>
<span>(37.7g / 34.7g/mole) x (3H2O / 1 Li3N) x 18g/mole = 58.67g required </span>
<span>1.08moles Li3N (1NH3 / 1Li3N) x 6.022x10^23molecules/mole = 6.54x10^23 molecules </span>
<span>10.3L at STP: 10.3L / 22.4L/mole = 0.46moles NH3 produced </span>
<span>0.46moles NH3 x (1Li3N / 1NH3) x 34.7g/mole = 15.96g</span>
The pure solvent sample will serve as the control for the experiment.
The properties of a solution are different from the properties of the pure substance or the pure solvents. For instance, if water and salt are mixed together to form salt solution, the properties of the water and that of the salt are different from that of the salt solution. Colligative properties refers to the properties of solutions which depend on the ratio of the number of solute particles to the number of solvent molecules in a solution; the properties do not depend on the chemical species that are present.<span />
Answer:

Explanation:
Hello,
By considering the rate law:
![ln(\frac{[CO_2]}{[CO_2]_0} )=-kt\\](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B%5BCO_2%5D%7D%7B%5BCO_2%5D_0%7D%20%29%3D-kt%5C%5C)
Solving for the time, we've got:
![k=-\frac{ln (\frac{[CO_2]}{[CO_2]_0 })}{t}\\\\k=-\frac{ln(\frac{56.0mmol*dm^{-3} }{220mmol*dm^{-3} })}{1.22x10^{4}s }\\ \\k=1.12x10^{-4}s](https://tex.z-dn.net/?f=k%3D-%5Cfrac%7Bln%20%28%5Cfrac%7B%5BCO_2%5D%7D%7B%5BCO_2%5D_0%20%7D%29%7D%7Bt%7D%5C%5C%5C%5Ck%3D-%5Cfrac%7Bln%28%5Cfrac%7B56.0mmol%2Adm%5E%7B-3%7D%20%7D%7B220mmol%2Adm%5E%7B-3%7D%20%7D%29%7D%7B1.22x10%5E%7B4%7Ds%20%7D%5C%5C%20%20%5C%5Ck%3D1.12x10%5E%7B-4%7Ds)
Best regards.
Answer:
60g/mol
Explanation:
By using nucleon numbers given on the periodic table, the mass of 1 mole of each element is:
C= 12g
H= 1g
O= 16g
Since molar mass is the sum of the masses of each element present in the compound,
Molar Mass (Mr) = 12+3(1)+12+16(2)+1 = 60g/mol
Answer: No
Explanation:
Example , Mercury is a Liquid metal