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3 years ago

1.State the relationship between the following properties:

Chemistry

1 answer:

Diano4ka-milaya [45]3 years ago

7 0

Answer:

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Name two metalloids that are semiconductors

guajiro [1.7K]

The Metalloids are:

Boron.

Silicon.

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2 years ago

In real-life situations, workers collect water samples in a lake or stream instead of using Samples A and B. For this lab to wor

Aloiza [94]

The given above pretty much states already that with the presence of the calcium carbonate which acts as the buffer will allow the solution to withstand changes in acidity. The greater the amount, the higher chances that it will be able to withstand the said changes. Therefore, if Lake X had greater ppm of CaCO3 then, it will be able to withstand greater amount of acid rain.

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2 years ago

Choose all the answers that apply.

zmey [24]

Calcium is a non metal

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3 years ago

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Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I

Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, $1.077\times 10^9$

Explanation :

First we have to calculate the moles of iron.

$\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles$

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains $6.022\times 10^{23}$ number of iron atoms

So, 0.0519 mole of iron contains $0.0519\times 6.022\times 10^{23}=3.125\times 10^{22}$ number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = $\frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}$

Number of iron atoms are present in each red blood cell = $\frac{3.125\times 10^{22}}{2.90\times 10^{13}}$

Number of iron atoms are present in each red blood cell = $1.077\times 10^9$

Therefore, the number of iron atoms present in each red blood cell are, $1.077\times 10^9$

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2 years ago

Select the correct answer. When an atom in a reactant loses electrons, what happens to its oxidation number? A. Its oxidation nu

vfiekz [6]

Answer:

C. Its oxidation number increases.

Explanation:

Oxidation is defined as the loss of electrons by an atom while reduction is the gain of electrons by an atom.
Atoms of elements have an oxidation number of Zero in their elemental state.
When an atom looses electrons it undergoes oxidation and its oxidation number increases.
For example, an atom of sodium (Na) at its elemental state has an oxidation number of 0. When the sodium atom looses an electrons it becomes a cation, Na+, with an oxidation number of +1 , the loss of electron shows an increase in oxidation number from 0 to +1.

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2 years ago

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