What are the slope and the y-intercept of the linear function that is represented by the equation y = negative 10 x + 1?

Mathematics

2 answers:

ser-zykov [4K]3 years ago

3 0

Answer:

gradient = -10

y intercept = 1

Step-by-step explanation:

y = mx + b

y = -10x + 1

m = slope ; hence, slope = -10 in the eqn

y intercept = when x = 0

y = -10(0) + 1

y = 1

antoniya [11.8K]3 years ago

3 0

Answer:

Step-by-step explanation:

Our equation is y = -10x + 1. Notice that this is of the form y = mx + b, which is called the slope-intercept form because it literally gives us the slope and y-intercept in the equation:

- m: this is the slope value

- b: this is the y-intercept

Here, m = -10, which means the slope is -10. Also, b = 1, so the y-intercept is 1.

Thus, the answer is B.

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Y = x² + 6x + 3

olganol [36]

Vertex is at $\left(-3,-6\right)$

y-intercept is 3.

The parabola opens up.

Step-by-step explanation:

The graph of the equation is hereby attached in the answer area.

Vertex is the point on the parabola where the graph crosses its axis of symmetry. The axis of symmetry here( $x =-3$ ), is shown with the dotted line in the graph attached.

y-intercept is defined as the value of y where the graph crosses the y-axis. In other words, when $x=0$ . Putting

And, the graph opens up as shown the graph figure as well. It is also evident from the co-efficient of $x$ in the given equation $y =x^{2} + 6x + 3$ . Here, co-efficient of