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alexdok [17]
3 years ago
6

How much work is done by the force of gravity when a 45 N object falls to the ground from a height of 4.6 m?

Physics
2 answers:
saul85 [17]3 years ago
5 0
Work Done = 45N x 4.6m = 207J
shutvik [7]3 years ago
4 0

Answer:

207Nm

Explanation:

Work on said to be done when an applied force causes an object to move through a particular distance. mathematically,

Work done = Force(f)×distance in the direction of force.

Given force of gravoty = 45N

Height = corresponding Distance= 4.6m

Work done = 45×4.6

Work done= 207Nm

This shows that 207Nm of work is done by the force of gravity when a 45 N object falls to the ground from a height of 4.6 m.

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A scientific theory is_____.
natta225 [31]

Answer:

B. A well-tested explanation for a widely accepted hypothesis

Explanation:

This is true about a scientific theory going by the fact of it being a well tested explanation. For example, in one of the Newtons law of motion which he stated to be<em> "To every action, there is equal and opposite reaction", </em><em>the hypothesis has been known till he was able to offer a well tested explanations with calculations showing that, it was actually true.</em>

6 0
3 years ago
White Blood Cells can be part of which body systems? (Choose all that<br> apply)
Lerok [7]

Answer:

Immune system

Explanation:

Because they defense our body act as 'Police of the body'.

4 0
4 years ago
Under constant pressure, the temperature of 2.43 mol of an ideal monatomic gas is raised 11.9 K. What are (a) the work W done by
const2013 [10]

Answer:

Explanation:

Given

no of moles n=2.43

Temperature raised \Delta T=11.9 k

Work done by gas

W=\int_{V_1}^{V_2}PdV

W=P\Delta V

W=nR\Delta T

W=2.43\times 8.314\times 11.9

W=240.41 kJ

(b)Energy Transferred as heat

Q=nc_p\Delta T

c_p=specific heat at constant Pressure

c_p for ideal Mono atomic gas is \frac{5R}{2}

Q=2.43\times \frac{5R}{2}\times 11.9

Q=601.03 kJ

(c)Change in Internal Energy

\Delta U=Q-W

\Delta U=601.03-240.41=360.62 kJ

(d)Change in average kinetic Energy \Delta k

K.E._{avg}=\frac{3}{2} \times k\times T

\Delta K.E.=\frac{3}{2} \times k\times \Delta T  ,where k=boltzmann constant

\Delta K.E.=\frac{3}{2}\times 1.38\times 10^{-23}\times 11.9

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3 0
3 years ago
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Alik [6]

Answer:

the answer is

Explanation:

constant acceleration

because when the object's velocity is changing then the object is accelerating or decelerating

as acceleration describe changing of velocity so the answer is constant acceleration

Acceleration is defined as the rate of change of velocity.

Acceleration = (Change in velocity) / time taken

Acceleration = (Final velocity - initial velocity) / time

As the object velocity changes by the same amount in each second, it means the acceleration is constant.

Hope I can help u

4 0
3 years ago
What is the velocity of a wave that has a frequency of 200 Hz and a<br> wavelength of 0.5m?
gladu [14]

Answer:

No idea now

Explanation:

wil get back to you in few minutes

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