All categories

2 years ago

How much work is done by the force of gravity when a 45 N object falls to the ground from a height of 4.6 m?

Physics

2 answers:

saul85 [17]2 years ago

5 0

Work Done = 45N x 4.6m = 207J

shutvik [7]2 years ago

4 0

Answer:

207Nm

Explanation:

Work on said to be done when an applied force causes an object to move through a particular distance. mathematically,

Work done = Force(f)×distance in the direction of force.

Given force of gravoty = 45N

Height = corresponding Distance= 4.6m

Work done = 45×4.6

Work done= 207Nm

This shows that 207Nm of work is done by the force of gravity when a 45 N object falls to the ground from a height of 4.6 m.

You might be interested in

How does friction affect moving objects?

Temka [501]

Friction will slow down the moving object

6 0

2 years ago

A 0.68 kg squirrel is resting on a branch 8 meters above the ground. What is the gravitational potential energy of a squirrel? A

ANEK [815]

Answer:

The gravitational potential energy of a squirrel is 53.312 J.

Explanation:

We have,

Mass of a squirrel is 0.68 kg

It is placed at a height of 8 m above the ground.

It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :

$E=mgh\\\\E=0.68\times 9.8\times 8\\\\E=53.312\ J$

So, the gravitational potential energy of a squirrel is 53.312 J.

7 0

2 years ago

A particle of mass 2 g travel a distance of 12 m in a time travel of 2 minute assuming the speed was constant find its kinetic e

balandron [24]

Answer:

0.00001 J

Explanation:

$k.e = \frac{1}{2} m {v}^{2} \\ = \frac{1}{2} (0.002) { ( \frac{12}{120} )} ^{2} \\ = 0.00001j$

3 0

2 years ago

A magnifier has a magnification of 8 x. How far from the lens should an object be placed so that it’s virtual image is at the ne

larisa86 [58]

The distance of the object from the lens is 3.12 cm.

<h3>What is magnification?</h3>

Magnification is the process of of enlarging an apparent size of an object.

<h3>Object distance</h3>

The object distance is calculated using the following lens formula;

$M = \frac{V}{U}$

where;

M is the magnification
V is the image distance
U is object distance

$- 8 = \frac{-25}{U} \\\\U = \frac{-25}{-8} \\\\U = 3.12 \ cm$

Thus, the distance of the object from the lens is 3.12 cm.

Learn more about object distance here: brainly.com/question/24894435

8 0

1 year ago

A light-year is the distance that light can travel in one year. If the sun is 1.5 x 10⁸ km away, how many light years is the sun

photoshop1234 [79]

Answer:

0.00001581 light years

Explanation:

distance divided by speed of light= 150,000,000/300,000= 500 seconds 8.3333

8.3 minutes

now divide this by 60 x 24 x 365.25. so you will get answer=

.000015823 light years.

3 0

2 years ago