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Ronch [10]
3 years ago
13

If there are 50 grams of U-238 on day zero of radioactive decay, how much will there be after 4.5 billion years? A) 0.0 grams B)

10 grams C) 25 grams D) 50 grams
Chemistry
2 answers:
Natalija [7]3 years ago
7 0

Answer:

= 25 g

Explanation:

Using the formula;

A = A₀ (1/2)^(t/h)

where A is the final amount,

A₀ is the initial amount of the substance,

t is the time and

h is the half-life of the substance,

In this case; the half life of U-238 h is equal to 4.47 billion years.

A = A₀ (1/2)^(t/h)

A = 50 (1/2)^(4.5 / 4.47)

   = 24.88

  <u> = 25 g</u>

otez555 [7]3 years ago
7 0

Answer:

C) 25 grams

Explanation:

25 grams would remain after one half-life (4.5 billion years). Find the point where percent remaining is 50% and that will tell you it is one half-life.

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Answer:

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Explanation:

: The corrosion of iron indicates a chemical change in the metal. ... Where salt is present, electrochemical corrosion occurs, and the protective oxide film does not form, thus the corrosion (buildup of rust) continues unchecked. Your iron nail will indeed rust more quickly and severely in salt water.

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What is an energy conserved system ?
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6 0
3 years ago
You push on the side of a toy truck rolling along the floor. What will happen to the motion of the truck?
sergeinik [125]

Answer:

The direction will be changed .

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3 0
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How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?
Dominik [7]
The grams   of glucose  are  needed  to  prepare  400g  of  a 2.00%(m/m)  glucose  solution  g  is  calculated  as  below

=% m/m =mass  of the solute/mass  of  the  solution  x100

let mass of   solute  be represented  by  y
mass  of solution = 400 g
 % (m/m) = 2% = 2/100

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5 0
3 years ago
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