Answer:- 12 km = 12000 m
Solution:- It's a metric unit conversion where we are asked to convert 12 km to m where km stands for kilometer and m stands for meter.
In metric conversions, kilo means 1000.
So, 1 km = 1000 m
It means, we multiply the given km by 1000 to get the answer in m as:
= 12000 m
Hence, 12 km = 12000 m.
There are a lot of ways to increase the solubility of the solute. <span>Increasing the temperature, mixing time and surface area of a solvent increases the solubility of the solute</span>
Enthalpy of formation is the alteration in enthalpy for the formation of one mole of the compound; hence you just have to modify the data you have proportionately to what it would be for one mole of the compound.
Begin with the balanced equation first, just to safeguard the coefficient on the substance you're given is 1, remembering that the coefficient on your product must be 1.
Na + (1/2)F2 --> NaF So no problem, since the coefficient of Na is 1. Change the mass of Na you're given to moles: (0.560 g Na)(1 mol Na/22.99 g Na) = 0.0244 mol Na. So, 13.8 kJ heat is altered by the response of 0.0244 mol Na.To look for the heat evolved by 1 mol Na, just divide the amount of heat by the number of moles: 13.8 kJ/0.0244 mol which gives 566.5 kJ/mol. Lastly, whether the heat is changed or obligatory to control the sign of ΔH. Heat is evolved here, meaning the reaction is exothermic, so ΔH = -566 kJ/mol.
Might be D bc it’s the only one that makes sense to me
Answer:
The final temperature of the water is 28.0 °C
Explanation:
Step 1: Data given
Mass of liquid water = 10.0 grams
Temperature = 23.0 °C
Heat absorbed = 209 Joules
Since heat was absorbed by the water, you must have a positive value for
Δ
T
Step 2: Calculate final temperature
q = m*c* ΔT
⇒ with m = the mass of the water = 10.0 grams
⇒ with c = the specific heat of water = 4.184 J/g°C
⇒ with ΔT = The change in temperature = T2 - T1 = T2 - 23.0 °C
⇒ with q = the heat absorbed = 209 Joule
209 = 10.0 * 4.184 * ΔT
ΔT = 5
ΔT = 5 = T2 - 23
T2 = 28 °C
The final temperature of the water is 28.0 °C
