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MAVERICK [17]
3 years ago
15

Help me Plaese

Physics
1 answer:
IRINA_888 [86]3 years ago
3 0

get a cylinder that is about maybe 100cm^3
fill it up with about 30cm^3
place the solid into the cylinder.
take the reading - 30 to find the volume of the solid
SI unit of length is meter
255cm=2550mm and 2.55m
about the scientists question: it'll be impossible to carry out experiments as science has to be very precise
1kg=1000g
1 fahrenheit = -17.2 degree celsius
milliliter

hope it helps :) need anything just msg 
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Basile [38]

Given.

force = 16.88 N is

radius = 0.340m

an angular acceleration = 1.20rad/s^2

the formula for torque is

F*r = I*a

where I is moment of inertia

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I = 4.78Kg-m^2

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3 years ago
Suppose humans have weights which are normally distributed with mean 170 lbs and SD 50 lbs. If 400 humans are selected at random
MrRa [10]

Answer:

 P(x< 175)= 0.9772

Explanation:

given,

mean weight of human = μ = 170 lbs

standard deviation = SD = 50 lbs

N = 400 humans

By using central limit theorem,

P (x< 175)

P(x< 175)= P(z

P(x< 175)= P(z

P (x< 175)= P(z

P (x< 175)= P(z

using z-table

 P (x< 175)= 0.9772

hence, the probability that total weight is less tan 175 lbs is equal to

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7 0
3 years ago
The force per meter between the two wires of a jumper cable being used to start a stalled car is 0.244 N/m. (a) What is the curr
MakcuM [25]

Answer: current I is 144amp(A)

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F/L is 0.244 N/m, pi is 3.142,

r is 1.7cm which is equal to 0.017meter.

I is what we are looking for.

Now we have after substitution,

0.244

= 1.257*EXP {-6} * I²/(2*3.142*0.017)

After cross multiplying and making I² subject of formula we have,

0.0261/(1.257*EXP {-6}) = I²

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8 0
3 years ago
A 4500 kg car accelerates from rest to 45.0
Llana [10]

The car undergoes an acceleration <em>a</em> such that

(45.0 km/h)² - 0² = 2 <em>a</em> (90 m)

90 m = 0.09 km, so

(45.0 km/h)² - 0² = 2 <em>a</em> (0.09 km)

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Ignoring friction, the net force acting on the car points in the direction of its movement (it's also pulled down by gravity, but the ground pushes back up). Newton's second law then says that the net force <em>F</em> is equal to the mass <em>m</em> times the acceleration <em>a</em>, so that

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8 0
4 years ago
Discussion Topic
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Explanation:

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