Answer:
Explanation:
Electric field E = 4 x 10⁷ V / m
Dielectric constant k = 24
capacitance of capacitor
C = kε₀ A / d
d = plate separation
A = plate area
C = .89 x 10⁻⁶
V / d = electric field
for minimum d , electric field will be maximum
V / d = 4 x 10⁷
1930 / d = 4 x 10⁷
d = 1930 / 4 x 10⁷
d = 482.5 x 10⁻⁷ m
= 48.25 x 10⁻⁶ m
C = kε₀ A / d
.89 x 10⁻⁶ = 24 ε₀ A / d
A = .89 x 10⁻⁶ X d / 24 ε₀
A = .89 x 10⁻⁶ X 48.25 x 10⁻⁶ / 24 x 8.85 x 10⁻¹²
= 42.9 / 212.4
= .2019 m²
Answer:
Uranus, Pluto, Neptune, Saturn , Jupiter, mars, Venus ,mercury and sun
Groundwater is the water found underground in the cracks and spaces in soil, sand and rock. It is stored in and moves slowly through geologic formations of soil, sand and rocks called aquifers.
Hope this helps.
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Answer:
= 15.57 N
= 2.60 N
= 16.98 N
The mass of the bag is the same on the three planets. m=1.59 kg
Explanation:
The weight of the sugar bag on Earth is:
g=9.81 m/s²
m=3.50 lb=1.59 kg
=m·g=1.59 kg×9.81 m/s²= 15.57 N
The weight of the sugar bag on the Moon is:
g=9.81 m/s²÷6= 1.635 m/s²
=m·g=1.59 kg× 1.635 m/s²= 2.60 N
The weight of the sugar bag on the Uranus is:
g=9.81 m/s²×1.09=10.69 m/s²
=m·g=1.59 kg×10.69 m/s²= 16.98 N
The mass of the bag is the same on the three planets. m=1.59 kg
A) 50 cm
B) 10000 cm/s
Explanation
Step 1
A)
If you know the distance between nodes and antinodes then use this equation:
![\begin{gathered} \frac{\lambda}{2}=D \\ \text{where}\lambda\text{ is the wavelength} \\ D\text{ is the distance betw}een\text{ nodes} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%5Clambda%7D%7B2%7D%3DD%20%5C%5C%20%5Ctext%7Bwhere%7D%5Clambda%5Ctext%7B%20is%20the%20wavelength%7D%20%5C%5C%20D%5Ctext%7B%20is%20the%20distance%20betw%7Deen%5Ctext%7B%20nodes%7D%20%5Cend%7Bgathered%7D)
then, let
![D=\text{ 25 cm }](https://tex.z-dn.net/?f=D%3D%5Ctext%7B%2025%20cm%20%7D)
now, replace to find the wavelength
![\begin{gathered} \frac{\lambda}{2}=25 \\ \text{Multiply both sides by 2} \\ \frac{\lambda}{2}\cdot2=25\cdot2 \\ \lambda=50\text{ Cm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%5Clambda%7D%7B2%7D%3D25%20%5C%5C%20%5Ctext%7BMultiply%20both%20sides%20by%202%7D%20%5C%5C%20%5Cfrac%7B%5Clambda%7D%7B2%7D%5Ccdot2%3D25%5Ccdot2%20%5C%5C%20%5Clambda%3D50%5Ctext%7B%20Cm%7D%20%5Cend%7Bgathered%7D)
so, the wavelength is
A) 50 cm
Step 2
The speed of a wave can be found using the equation
![v=\lambda f](https://tex.z-dn.net/?f=v%3D%5Clambda%20f)
or velocity = wavelength x frequency,
then,let
![\begin{gathered} \lambda=50\text{ cm} \\ f=200\text{ Hz} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Clambda%3D50%5Ctext%7B%20cm%7D%20%5C%5C%20f%3D200%5Ctext%7B%20Hz%7D%20%5Cend%7Bgathered%7D)
replace and evaluate
![\begin{gathered} v=\lambda f \\ v=50\text{ cm }\cdot200\text{ HZ} \\ v=10000\text{ }\frac{\text{cm}}{s} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20v%3D%5Clambda%20f%20%5C%5C%20v%3D50%5Ctext%7B%20cm%20%7D%5Ccdot200%5Ctext%7B%20HZ%7D%20%5C%5C%20v%3D10000%5Ctext%7B%20%7D%5Cfrac%7B%5Ctext%7Bcm%7D%7D%7Bs%7D%20%5Cend%7Bgathered%7D)
so
B) 10000 cm/s
I hope this helps you