0 N. It's being pushed up the same amount it's being pushed down, so it cancels out.
A few different ways to do this:
Way #1:
The current in the series loop is (12 V) / (total resistance) .
(Turns out to be 2 Amperes, but the question isn't asking for that.)
In a series loop, the current is the same at every point, so it's
the same current through each resistor.
The power dissipated by a resistor is (current)² · (resistance),
and the current is the same everywhere in the circuit, so the
smallest resistance will dissipate the least power. That's R1 .
And by the way, it's not "drawing" the most power. It's dissipating it.
Way #2:
Another expression for the power dissipated by a resistance is
(voltage across the resistance)² / (resistance) .
In a series loop, the voltage across each resistor is
[ (individual resistance) / (total resistance ] x battery voltage.
So the power dissipated by each resistor is
(individual resistance)² x [(battery voltage) / (total resistance)²]
This expression is smallest for the smallest individual resistance.
(The other two quantities are the same for each individual resistor.)
So again, the least power is dissipated by the smallest individual resistance.
That's R1 .
Way #3: (Einstein's way)
If we sat back and relaxed for a minute, stared at the ceiling, let our minds
wander, puffed gently on our pipe, and just daydreamed about this question
for a minute or two, we might have easily guessed at the answer.
===> When you wire up a battery and a light bulb in series, the part
that dissipates power, and gets so hot that it radiates heat and light, is
the light bulb (some resistance), not the wire (very small resistance).
Answer:
E; The object is negatively charged
Explanation:
Here, we want to state the conclusion that can be drawn from a positively charged rod being attracted to an object.
Generally as we know, oppositely charged materials attract while the ones with same charges repel each other.
Thus, in this case, for the rod to attract the object, there must have been an opposite charge of negativity on the object
So we conclude that the reason why the rod attracted the object was because of the presence of opposing charges on both of them. And since the rod has taken the positive charge, it is only correct to state that the object is negatively charged
B. Conductors allow electricity to go through them only. Such as copper etc.
Answer:
250 m
Explanation:
In projectile, range is given as;
R = (v²sin 2θ)/g
We are given θ = 45°
Thus range of shell is;
R = (v²sin (2 × 45))/g
R = v²/g
Now, distance for the shell to hit the car will be; 150 + 14.14t
This will be equal to the range of shell;
150 + 14.14t = v²/g
Where t is time of flight
Now, time of flight is given by;
t = (2vsin θ)/g
t = (2v sin 45)/g
In surf form, we have;
t = (2v/(g√2))
Simplifying further gives;
t = (v√2)/g
Plugging this value of t into the distance equation gives;
150 + 14.14(v√2)/g = v²/g
Assuming g is 10 m/s², we have;
150 + 14.14(v√2)/10 = v²/10
Multiply through by 10 to get;
1500 + 14.14(v√2) = v²
v² - 20v - 1500 = 0
From quadratic equation calculator, we have; v = 50 m/s
Thus, t = (50√2)/g
t = (50√2)/10
t = 5√2
Plugging this into the distance equation gives;
Distance = 150 + 14.14(5√2) = 250 m
