Answer:
38.6 N
2.57 m/s²
Explanation:
Draw a free body diagram of the box. There are four forces:
Weight force mg pulling down,
Normal force N pushing up,
Friction force Nμ pushing left,
and applied force P pulling at an angle 40°.
Sum of forces in the y direction:
∑F = ma
N + P sin 40° − mg = 0
N = mg − P sin 40°
The net force in the x direction is:
∑F = P cos 40° − Nμ
∑F = P cos 40° − (mg − P sin 40°) μ
∑F = P cos 40° − mgμ + Pμ sin 40°
∑F = P (cos 40° + μ sin 40°) − mgμ
Plugging in values:
∑F = (80 N) (cos 40° + 0.23 sin 40°) − (15 kg) (10 m/s²) (0.23)
∑F = 38.6 N
Net force equals mass times acceleration:
∑F = ma
38.6 N = (15 kg) a
a = 2.57 m/s²
Answer:
9.8N
Explanation:
Here we can get gravitational acceleration according to the place where object is placed by bellow equation
g = GM/R²
g - Gravitational Acceleration
G - Gravitational constant (6.67×10-11)
R - Distance ( Radius )
g = 6.67 × 10-11 × 1024 /(6.37×106)²
g = 9.8 m/s²
There for
Weight = Mass × Gravitational acceleration
= 1×9.8
= 9.8 N
It means that the car has covered
(35 miles) x (the number of hours since it started traveling).
At some points during that time, the car was most likely moving
faster or slower than 35 miles per hour. We don't know. We only
know that it covered (35 miles) x (the number of hours since it left).
Answer:
is correct
Explanation:
in my think, first this due to ray emitted from the light those ray may be affect our skin or party of body.