False. That description fits the wave's 'frequency'.
It has nothing to do with refraction.
Tom used more Force but over a shorter distance. Tom and Claudia both did the same amount of work.
Then the maximum height of the catapult will be 69.78 meters.
<h3>What is kinematics?</h3>
The study of motion without considering the mass and the cause of the motion. The equation of motion is given below.
v = u + at
s = ut + (1/2)at²
v² = u² + 2as
A catapult can project a projectile at a speed as high as 37.0 m/s. (a) if air resistance can be ignored.
a = - 9.81 m/s²
u = 37 m/s
v = 0
s = h
Then the maximum height of the catapult will be given by the third equation.
v² = u² + 2as
0² = 37² - 2 × 9.81 × h
h = 37² / (2 × 9.81)
h = 69.78 meters
Then the maximum height of the catapult will be 69.78 meters.
More about the kinematics link is given below.
brainly.com/question/7590442
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Answer:
6 km/h west
Explanation:
During part c of the hike, the hiker moved 6 km west, and the time was 9.45 am to 10.45 am.
So, we have:
- displacement: d = 6 km west
- time taken: from 9.45 am to 10.45 am = 1 hour
Therefore, the average velocity is given by the ratio between displacement and time taken:

and the direction is the same as the displacement (west)
Answer
given,
constant speed of cart on right side = 2 m/s
diameter of nozzle = 50 mm = 0.05 m
discharge flow through nozzle = 0.04 m³
One-fourth of the discharge flows down the incline
three-fourths flows up the incline
Power = ?
Normal force i.e. Fn acting on the cart

v is the velocity of jet
Q = A V


v = 20.37 m/s
u be the speed of cart assuming it to be u = 2 m/s
angle angle of inclination be 60°
now,

F n = 2295 N
now force along x direction



Power of the cart
P = F x v
P = 1987.52 x 20.37
P = 40485 watt
P = 40.5 kW