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kolezko [41]
3 years ago
10

A system is initially at conditions of

Physics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

a)W=20 KJ

b) ΔQ= 220 KJ

Explanation:

Given:

V₁=0.1 m^3,   P₁=200 kPa and heat is added to the system such that system expands under constant pressure.

Therefore V₂= 2V₁= 0.2 m^3

a) Work transfer W= P(V₂-V₁)= 200\times(0.2-0.1)\times10^{5} = 2\times10^4 joules

W=20 KJ

b) internal energy change ΔU= 200 KJ

from first law we know that ΔQ(net heat transfer)= ΔU + W

ΔQ= 200\times10^3 +2\times10^4

ΔQ=22\times10^4 J

ΔQ= 220 KJ

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