Question

A system is initially at conditions of

Answer 1

Answer:

a)W=20 KJ

b) ΔQ= 220 KJ

Explanation:

Given:

V₁=0.1 m^3,   P₁=200 kPa and heat is added to the system such that system expands under constant pressure.

Therefore V₂= 2V₁= 0.2 m^3

a) Work transfer W= P(V₂-V₁)= $200\times(0.2-0.1)\times10^{5} = 2\times10^4 joules$

W=20 KJ

b) internal energy change ΔU= 200 KJ

from first law we know that ΔQ(net heat transfer)= ΔU + W

ΔQ= $200\times10^3 +2\times10^4$

ΔQ=$22\times10^4 J$

ΔQ= 220 KJ