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3 years ago

UPVOTE FOR EVERY ANSWER!

Physics

1 answer:

agasfer [191]3 years ago

4 0

<span>C. From positive to negative terminals

Hope this helps!</span>

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A stone is dropped from a cliff and falls 9.44 meters. What is the speed of the stone when it reaches the ground?

Lunna [17]

Answer:

option A

Explanation:

given,

height of the drop of stone = 9.44 m

speed of the stone = ?

As the stone is dropped the energy of the stone will be conserved.

using conservation of energy.

Potential energy = Kinetic energy

$m g h = \dfrac{1}{2} m v^2$

$v = \sqrt{2gh}$

$v = \sqrt{2\times 9.8 \times 9.44}$

$v = \sqrt{185.024}$

v = 13.60 m/s

Hence, the correct answer is option A

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3 years ago

What effect does a catalyst have on a system in equilibrium?

Jet001 [13]

ANSWER:

What effect does a catalyst have on a system in equilibrium?

The system is unaffected.

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3 years ago

A roller coaster has a mass of 275 kg. It sits at the top of a hill with height 85 m. If it drops from this hill, how fast is it

Minchanka [31]

kinematic equation

v squared = u squared + 2 a x s

v= sq root (0 + 2 10 x 65)

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4 0

3 years ago

Read 2 more answers

Will give brainliest to correct answer!

ad-work [718]

The international system of units is the designated system of units used by scientist in every part of the world to keep data in the same form and measurements, this is to avoid confusion and the need to convert data when being shared. typically described in meters or kilometer over a time form usually seconds or hours.

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3 years ago

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A solid brass cylinder and a solid wood cylinder have the same radius and mass (the wood cylinder is longer). Released together

Lena [83]

Answer:

a. They will be tie

b. Win the wood cylinder

Explanation:

The both cylinders will reach the bottom at the same time notice the relation in the equation in indepent of the length and both have the same radius and the same rotational inertia.

$I=\frac{1}{2}*m*r^2$

$a=\frac{g*sin(\beta)}{1+I_{com}/m*r^2}$

So both will be tie

$a_{brass}=\frac{g*sin(\beta)}{1+I_{brass}/m*r^2}=a_{wood}=\frac{g*sin(\beta)}{1+I_{wood}/m*r^2}$

The acceleration of the wood cylinder is larger than the acceleration of the brass cylinder so the cylinder of wood will reach the bottom first

$a_{brass}$

So the wood win the race

6 0

3 years ago