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galina1969 [7]
2 years ago
15

A bag of sugar weights 20 N on the earths surface. If you double the distance from the center of the earth, the bag now weighs w

hat
Physics
1 answer:
elena-s [515]2 years ago
4 0
I have no idea that’s a hard one
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The surface of the Earth changes from processe such as erosion. Which of these changes to Earth's surface is an example of erosi
Ad libitum [116K]

Answer:

D. the wind picking up dust and carrying it

Explanation:

Erosion is a process in which an agent transfer the top soil to another region, thereby exposing the lower soil. These agents have the ability to move the top layer of soil and deposit it at another place. The major agents in this case are; a running or flowing body of water and wind.

Therefore, the change to the Earth's surface that is an example of erosion is the wind picking up dust and carrying it. Thereby exposing the lower layers.

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2 years ago
What is cosmic background radiation?
Kobotan [32]
Cosmic background radiation is electromagnetic radiation from the sky with no discernible source. The origin of this radiation depends on the region of the spectrum that is observed. 
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3 years ago
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If you traveled 90 km in 0.50 hours, what <br><br> was your average speed
Alinara [238K]

Average speed = distance / time

Average speed = 90 km / 0.5 hrs

Average speed = 180 km per hour

8 0
3 years ago
Please Help me with any of these possible.
Fiesta28 [93]

alll factor is possible

4 0
3 years ago
The density of molybdenum is 10.28 g/cm^3 and it crystallizes in the face centered cubic unit cell. Calculate the edge length of
Effectus [21]

The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

<h3>Volume of molybdenum</h3>

V = (zm/ρN)

where;

  • z is 2 for cubic unit cell
  • m is mass of the molybdenum
  • ρ is density of the molybdenum

V = (2 x 95.96) / (10.28 x 6.02 x 10²³)

V = 3.10 x 10⁻²³ cm³

<h3>Edge length of the unit cell</h3>

a³ = V

a = (V)^¹/₃

a = ( 3.10 x 10⁻²³)^¹/₃

a = 3.142 x 10⁻⁸ cm

a = 3.142 x 10⁻¹⁰ m

a = 314.2 x 10⁻¹² m

a = 314.2 pm

Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

Learn more about edge length here:

brainly.com/question/16673486

#SPJ1

4 0
2 years ago
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