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Anettt [7]
3 years ago
7

Janel did an experiment to see which spices can kill bacteria. She mixed a spice with bacteria food called agar. She poured the

agar and spice mix into a petri dish(a plate used for growing bacteria) and added bacteria. She did the same for five different spices. This is an example of
Physics
1 answer:
LenKa [72]3 years ago
6 0

Answer:

Antibacterial activity

Explanation:

The antibacterial property does not allow bacterias to live in an environment. Many spices have the ability to show antibacterial activity, few of these spices can be named as cinnamon, turmeric, or clove. Because they have antimicrobial or antibacterial characteristics that is why they are used for food preservation, disease prevention, and provide many health benefits. But, not every spice has antibacterial characteristics, that is why Janel experimented with five different spices to see which amongst them possess antibacterial characteristics.

Hence the correct answer is Antibacterial activity.

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Nuclear energy is..
AlexFokin [52]

I am going to say

C.  Energy contained in the nucleus of an atom

4 0
3 years ago
A litre of a gas weigh 2 gram at 300 kelvin temperature and 1 atm pressure,if the pressure is made 75 atm then at which temperat
liberstina [14]

Answer:

45000 K .

Explanation:

Given :

A liter of a gas weigh 2 gram at 300 kelvin temperature and 1 atm pressure

We need to find the temperature in which 1 litre of the same gas weigh 1 gram

in pressure 75 atm.

We know, by ideal gas equation :

PV=nRT

Here , n is no of moles , n=\dfrac{Given \ Weight }{Molecular\ Mass}=\dfrac{w}{M}

Putting initial and final values and dividing them :

\dfrac{P_1V_1}{P_2V_2}=\dfrac{\dfrac{w_1}{M}T_1}{\dfrac{w_2}{M}T_2}

\dfrac{1\times 1}{75\times 1}=\dfrac{\dfrac{2}{M}\times 300}{\dfrac{1}{M}\times T_2}\\ \\T_2=45000\ K.

Hence , this is the required solution.

7 0
3 years ago
g A loop circuit has a resistance of R1 and a current of 2 A. The current is reduced to 1.4 A when an additional 2.2 Ω resistor
Mrrafil [7]

Answer:

R1 = 5.13 Ω

Explanation:

From Ohm's law,

V = IR............... Equation 1

Where V = Voltage, I = current, R = resistance.

From the question,

I = 2 A, R = R1

Substitute into equation 1

V = 2R1................ Equation 2

When a resistance of 2.2Ω is added in series with R1,

assuming the voltage source remain constant

R = 2.2+R1,  and I = 1.4 A

V = 1.4(2.2+R1)................. Equation 3

Substitute the value of V into equation 3

2R1 = 1.4(2.2+R1)

2R1 = 3.08+1.4R1

2R1-1.4R1 = 3.08

0.6R1 = 3.08

R1 = 3.08/0.6

R1 = 5.13 Ω

6 0
3 years ago
A 160cm long string has two adjacent resonance at 85hz frequencies . calculate : 1- the fundamental frequency , 2- the speed of
lara [203]

Length=l=160cm=1.6m

Frequency=85Hz

#1

Fundamental frequency be v

\\ \sf\bull\longmapsto v=\dfrac{\nu}{2\ell}

\\ \sf\bull\longmapsto v=\dfrac{85}{2(1.6)}

\\ \sf\bull\longmapsto v=\dfrac{85}{3.2}

\\ \sf\bull\longmapsto v=26.6Hz

#2

First we have to find wavelength

\\ \sf\bull\longmapsto \lambda=\dfrac{c}{v}

\\ \sf\bull\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{26.6}

\\ \sf\bull\longmapsto \lambda=0.112\times 10^8m

\\ \sf\bull\longmapsto \lambda=112\times 10^5m

\\ \sf\bull\longmapsto \lambda=1.12\times 10^6m

Now..

Velocity be v

\\ \sf\bull\longmapsto v=f\lambda

  • f is frequency

\\ \sf\bull\longmapsto v=26.5\times1.12\times 10^6m

\\ \sf\bull\longmapsto v=29.68\times 10^6

\\ \sf\bull\longmapsto v=2.9\times 10^7m/s

5 0
3 years ago
Which of the following statements concerning statistical probability is not true? A. Probability involves the level of certainty
Leto [7]
The answer to this is D. Probability levels for finding statistical significance increase as statistical power decreases. The statement concerning statistical probability is not true as this is d.

I hope this helps!
8 0
3 years ago
Read 2 more answers
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