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Whitepunk [10]
3 years ago
8

Help with this voltage drop? I'd also like to know how you did it.

Physics
1 answer:
grandymaker [24]3 years ago
4 0
No one answeres physic questions, iveneeded help all morning
 
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Where is the 3rd quadrant
jeka94

The 3rd Quadrant is the lower left one on a graph,
where  ' x '  and  ' y '  are both negative.

Your picture is completely unrelated to this question.


4 0
3 years ago
a small negatively charged sphere with a mass of 5.4*10^-5 is suspended between two parallel plates. the potential difference is
labwork [276]
Here, Fe = Fg
q.E = m.g
We have: E = 360 V
m = 5.4 × 10⁻⁵
g = 9.8 m/s²   [ constant value for earth system ]

Substitute their values into the expression:
q (360) = 5.4 × 10⁻⁵ × 9.8
q = 52.92 × 10⁻⁵ / 360
q = -1.47 × 10⁻⁶  [ negative sign represents the nature of charge ] 

So, Your Final answer would be 1.47 × 10⁻⁶

Hope this helps!
3 0
3 years ago
vector a having mignitude 3.2 makes 50degre with x-axis and vector b with magnitude 5.2 makes 110degre with x-axis what is the m
Svetllana [295]
Yep ask google good idea
8 0
3 years ago
Besides adding adaptive optics to a telescope, what else can be done to reduce the effects of seeing?
anyanavicka [17]
<span>There is an low cost and quickest alternative available for adaptive optics. Name of this technique is wavefront coding. The numerical analysis pretends to show the robustness of the technique under changes in pupil diameter and wavefront shape including intersubject and intrasubject variability, using always the same restoration filter or image decoder .Using this technique it is possible to obtain high resolution images under different ocular aberrations and pupil diameters with the same decoder, opening the possibility of real time high resolution images.</span>
7 0
2 years ago
A body of mass m moves along y such that at time t its position is y(t)= at^2 – bt + c, where a, b, c are constant.
Akimi4 [234]

Answer:

what do u need help with

Explanation:

A body of mass m moves along X-axis such that its position co-ordiante at any instant t is x = `at^(4)

3 0
3 years ago
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